1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Genrish500 [490]
3 years ago
5

A plastic ball of mass 0.200 kg moves with a velocity of 0.30 m/s. This plastic ball collides with a second plastic ball of mass

0.100 kg that is moving along the same line at a velocity of 0.10 m/s. After the collision, the velocity of the 0.100 kg ball is 0.36 m/s. What is the velocity of the second ball?
Physics
1 answer:
GrogVix [38]3 years ago
8 0
<h2>Velocity of 0.2 kg ball is 0.17 m/s</h2>

Explanation:

Let the mass of balls be m and M.

Initial velocity ball 1 be u₁, ball 2 be u₂

Final velocity ball 1 be v₁, ball 2 be v₂

Initial momentum = m x u₁ + M x u₂ = 0.2 x 0.3 + 0.1 x 0.1 = 0.07 kgm/s

Final momentum = m x v₁ + M x v₂ = 0.2 x v₁ + 0.1 x 0.36 = 0.2v₁ + 0.036

We have momentum conservation

Initial momentum = Final momentum

0.07 = 0.2v₁ + 0.036

v₁ = 0.17 m/s

Velocity of 0.2 kg ball is 0.17 m/s

You might be interested in
what happens if a voltmeter is connected in series with other components of the circuit (i.e , ammeter, cell, battery, resistor
Talja [164]

Answer:the voltmeter measures the potential difference of the circuit,. Voltmeter is a device used to measure potential difference.

Explanation:

8 0
3 years ago
A thundercloud has an electric charge of 48.8 C near the top of the cloud and –41.7 C near the bottom of the cloud. The magnitud
IceJOKER [234]

Answer: 1.51 km

Explanation:

<u>Coulomb's Law:</u> The electrostatic force between two charge particles Q: and Q2 is directly proportional to product of magnitude of charges and inversely proportional to square of separation distance between them.

Or,   \vec{F}=k \frac{Q_{1} Q_{2}}{r^{2}}

Where Q1 and Q2 are magnitude of two charges and r is distance between them:

<u>Given:</u>

Q1 = Charge near top of cloud = 48.8 C

Q2 = Charge near the bottom of cloud = -41.7 C

Force between charge at top and bottom of cloud (i.e. between Q: and Q2) (F) = 7.98 x 10^6N

k = 8.99 x 109Nm^2/C^2

<u>So,</u>

\begin{aligned}&7.98 \times 10^{6}=\left(8.99 \times 10^{9} \mathrm{Nm}^{2} / \mathrm{C}^{2}\right) \frac{48.8 \mathrm{C} \times 41.7 \mathrm{C}}{\mathrm{r}^{2}} \\&r=\sqrt{\frac{1.8294 \times 10^{13}}{7.98 \times 10^{6}}}=1.514  \times 10^{3} \mathrm{~m}=1.51 \mathrm{~km}\end{aligned}

Therefore, the separation between the two charges (r) = 1.51 km

3 0
2 years ago
One end of a thin rod is attached to a pivot, about which it can rotate without friction. Air resistance is absent. The rod has
Mars2501 [29]

Answer:

6.86 m/s

Explanation:

This problem can be solved by doing the total energy balance, i.e:

initial (KE + PE)  = final (KE + PE). { KE = Kinetic Energy and PE = Potential Energy}

Since the rod comes to a halt at the topmost position, the KE final is 0. Therefore, all the KE initial is changed to PE, i.e, ΔKE = ΔPE.

Now, at the initial position (the rod hanging vertically down), the bottom-most end is given a velocity of v0. The initial angular velocity(ω) of the rod is given by ω = v/r , where v is the velocity of a particle on the rod and r is the distance of this particle from the axis.

Now, taking v = v0 and r = length of the rod(L), we get ω = v0/ 0.8 rad/s

The rotational KE of the rod is given by KE = 0.5Iω², where I is the moment of inertia of the rod about the axis of rotation and this is given by I = 1/3mL², where L is the length of the rod. Therefore, KE = 1/2ω²1/3mL² = 1/6ω²mL². Also, ω = v0/L, hence KE = 1/6m(v0)²

This KE is equal to the change in PE of the rod. Since the rod is uniform, the center of mass of the rod is at its center and is therefore at a distane of L/2 from the axis of rotation in the downward direction and at the final position, it is at a distance of L/2 in the upward direction. Hence ΔPE = mgL/2 + mgL/2 = mgL. (g = 9.8 m/s²)

Now, 1/6m(v0)² = mgL ⇒ v0 = \sqrt{6gL}

Hence, v0 = 6.86 m/s

4 0
3 years ago
ADP binds to platelets in order to intiate the activation process. Two binding sites were identified on platelets, one with a Kd
12345 [234]

Answer:B) The binding site with a kid of7.9uM is the low affinity site.

Explanation:

The rate at which macro molecules like protein bind together is called affinity. The higher the affinity site the more readily these macro molecules fuses together. 7.9uM is a low affinity value than 359uM.

5 0
3 years ago
Sound waves are classified as which type of wave?answer
iren [92.7K]
The answer is D. I hope this helps
4 0
3 years ago
Other questions:
  • To investigate seed growth in different levels of light, Jarrod covers seeds with soil in three different containers. He places
    7·2 answers
  • Explain it with method....
    5·2 answers
  • Compare and contrast scientific theory and scientific law
    13·1 answer
  • What does the statement “10 m/s to the north” describe? A. time B. velocity
    7·2 answers
  • Several motorboats with the same mass are used in an experiment. The forces of the different motors versus their accelerations a
    8·1 answer
  • A kickoff sends a football with an initial velocity of 25 m/s at an angle of 50
    15·1 answer
  • Which of the following has the least resistance?<br><br> wood<br> iron<br> copper<br> silver
    15·1 answer
  • When a 100-N force acts horizontally on an 8.0-kg chair, the chair moves at a constant speed across the level floor. Which state
    9·1 answer
  • A 10-cm-long thin glass rod uniformly charged to 5.00 nc and a 10-cm-long thin plastic rod uniformly charged to - 5.00 nc are pl
    10·1 answer
  • NEED HELP ASAP Which of the following chemical equations shows the Law of Conservation of Mass? (1 point)
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!