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AlekseyPX
3 years ago
9

Sound waves are classified as which type of wave?answer

Physics
1 answer:
iren [92.7K]3 years ago
4 0
The answer is D. I hope this helps
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If the resistance is not changed but the voltage is increased, what happens to the current
julsineya [31]

We know that According to Ohm's Law :

Current passing through a Conductor is directly proportional to the Voltage over a given Resistance.

⇒ V ∝ I

⇒ V = I × R

If Resistance is not changed and Voltage is increased, Based on Ohm's law we can conclude that Current flowing will also increase, because Voltage is directly proportional to Current.

6 0
3 years ago
Find the mass of an object on planet F if its weight is 650 N (g = 13m/s^2)
Andrew [12]

Answer:

the object's mass is 50 kg

Explanation:

We use Newton's second law to solve for the mass:

F = m * a , then   m = F / a

In our case, the acceleration is the gravitational acceleration on the planet, and the force is the weight of the object on the planet. So we get:

m = w / a = 650 N / 13 m/s^2 = 50 kg

Then, the object's mass is 50 kg.

5 0
3 years ago
Which sentence states Newton’s third law?
hammer [34]
<span>If two objects collide, each object exerts a force equal to and in the opposite direction of the other.</span>
3 0
3 years ago
Read 2 more answers
It's important to do cardiovascular exercise on a regular basis because it _____.
n200080 [17]

Answer:

I believe it improves your hearts stroke volume

If im wrong plz let me know

4 0
3 years ago
2
Xelga [282]

Answer:

About 7.67 m/s.

Explanation:

Mechanical energy is always conserved. Hence:

\displaystyle \begin{aligned} E_i & = E_f \\ \\ U_i + K_i &= U_f + K_f\end{aligned}

Where <em>U</em> is potential energy and <em>K</em> is kinetic energy.

Let the bottom of the slide be where potential energy equals zero. As a result, the final potential energy is zero. Additionally, because the child starts from rest, the initial kinetic energy is zero. Thus:

\displaystyle U_i = K_f

Substitute and solve for final velocity:
\displaystyle \begin{aligned} mgh_i &= \frac{1}{2}mv_f^2 \\ \\  2gh_i &= v^2_f \\ \\ v_f &= \sqrt{2gh_i} \\ \\ &  =\sqrt{2(9.8\text{ m/s$^2$})(3.00\text{ m})} \\ \\ & \approx 7.67\text{ m/s} \end{aligned}

In conclusion, the child's speed at the bottom of the slide is about 7.67 m/s.

8 0
2 years ago
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