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4 years ago

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ADP binds to platelets in order to intiate the activation process. Two binding sites were identified on platelets, one with a Kd

of 350 nM and one with a Kd of 7.9 µM. Which of these is the low-affinity binding site? A) The binding site with a Kd of 350 nM is the low affinity site. B) The binding site with a Kd of 7.9 µM is the low affinity site. C) No way to tell

1 answer:

12345 [234]4 years ago

5 0

Answer:B) The binding site with a kid of7.9uM is the low affinity site.

Explanation:

The rate at which macro molecules like protein bind together is called affinity. The higher the affinity site the more readily these macro molecules fuses together. 7.9uM is a low affinity value than 359uM.

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A train is pulling four train cars and each car has a mass of 40,000 kg. The train is accelerating at 1.1 m/s^2. What is the for

IgorLugansk [536]

Answer:

176,000 N

Explanation:

Newton's second law:

∑F = ma

F = (4 × 40,000 kg) (1.1 m/s²)

F = 176,000 N

8 0

4 years ago

Read 2 more answers

An inverted image of an object is viewed on a screen from the side facing a converging lens. An opaque card is then introduced c

Marta_Voda [28]

Answer:

d) The image would be dimmer

Explanation:

When inverted image of an object is viewed on a screen from the side facing a converging lens, the

lens focuses the diverging, and blurred light rays from the distance object through refraction of the rays two times.Then the rays is converge by the double bending cl at a focal point behind the lens inorder for a sharper image to be be observed.

But when an opaque card is then introduced to cover only the upper half of the lens then the image becomes dimmer because of the reduction in the light intensity on the screen by 50%

5 0

3 years ago

ANSWERED: An object with a massive 5 kg is thrown with an initial velocity of 6 m/s. If the object has an initial height of 10 m

vodka [1.7K]

Explanation:

The velocity is not needed. (its needed to find kinetic energy but its irrelevant to the question)

Potential energy = Mgh

Mass=5kg, height=10meters, g=9.8

P.e=5×9.8×10

=5×98

=490 joules

Hope it helps

:)

4 0

3 years ago

The length of a bicycle pedal arm is 0.177 m, and a downward force of 145 N is applied to the pedal by the rider. What is the ma

kramer

Answer:

(a) 19.25 N-m

(b) 25.67 N-m

(c) 0 N-m

Explanation:

Given:

Length of the pedal arm (L) = 0.177 m

Downward force $(|\vec{F}|)$ = 145 N

Magnitude of torque is given by the formula:

$T=FL\sin\theta$

Where, $\theta\to angle\ between\ F\ and\ L$

(a)

Given:

$\theta=48.6$ °

Therefore, torque is given as:

$T=FL\sin\theta\\\\T=(145\ N)(0.177\ m)(\sin(48.6))\\\\T=19.25\ Nm$

Therefore, the torque is 19.25 N-m.

(b)

Given:

$\theta=90$ °

Therefore, torque is given as:

$T=FL\sin\theta\\\\T=(145\ N)(0.177\ m)(\sin(90))\\\\T=25.67\ Nm$

Therefore, the torque is 25.67 N-m.

(c)

Given:

$\theta=180$ °

Therefore, torque is given as:

$T=FL\sin\theta\\\\T=(145\ N)(0.177\ m)(\sin(180))\\\\T=0\ Nm$

Therefore, the torque is 0 N-m.

8 0

3 years ago

A 480N sphere 40.0cm in radius rolls without slipping 1200cm down a ramp that is inclined at 53 0 with the horizontal. What is t

IgorC [24]

As we know that sphere roll without slipping so there is no loss of energy in this case

so here we can say that total energy is conserved

Initial Kinetic energy + initial potential energy = final kinetic energy + final potential energy

$\frac{1}{2}mv_i^2 + mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega^2+ mgh'$

as we know that ball start from rest

$v_i = 0$

height of the ball initially is given as

$h = Lsin\theta$

$h = 1200sin53 = 960 cm$

also we know that

$I = \frac{2}{5}mR^2$

also for pure rolling

$v = r\omega$

also we know that

$480 = m*9.8$

$m = 49 kg$

now plug in all data in above equation

$480*9.60 + 0 = \frac{1}{2}*49*(0.40*\omega)^2 + \frac{1}{2}*\frac{2}{5}*49*(0.40)^2\omega^2 + 0$

$4608 = 3.92\omega^2 + 1.568\omega^2$

$\omega^2 = 839.65$

$\omega = 29 rad/s$

So speed at the bottom of the inclined plane will be 29 rad/s

7 0

4 years ago