The Lewis dot diagram structure for hydrogen cyanide would be the following:
H - C --- N
--- = triple bond.
Answer:
- The first picture attached is the diagram that accompanies the question.
- The<u> second picture attached</u> is the diagram with the answer.
Explanation:
In the box on the left there are 8 Cl⁻ ions and 8 Na⁺ ions.
The dissociaton equation for NaCl(aq) is:
- NaCl (aq) → Na⁺ (aq) + Cl⁻(aq)
The dissociation equation for CaCl₂ (aq) is:
- CaCl₂ (aq) → Ca²⁺ (aq) + 2Cl⁻(aq)
A 0.10MCaCl₂ (aq) solution will have half the number of CaCl₂ units as the number of NaCl units in a 0.20M NaCl (aq) solution.
Thus, while the 0.20M NaCl (aq) solution yields 8 ions of Na⁺ and 8 ions of Cl⁻, the 0.10MCaCl₂ (aq) solution will yield 4 ions of Ca²⁺ (half because the concentration if half) and 8 ions of Cl⁻ (first take half and then multiply by 2 because the dissociation reaction).
Thus, your drawing must show 4 dots representing Ca²⁺ ions and 8 dots representing Cl⁻ ions in the box on the right.
Answer:
262.8 g
Explanation:
Molarity = 3.0M
Mass = ?
Volume = 2.40L
The relationship between these quantities is given as;
Molarity = Number of moles / Volume
Number of moles = Molarity * Volume
Number of moles = 3 * 2.4 = 7.2 mol
Mass = Number of moles * Molar mass
Molar mass of HCl = 1 + 35.5 = 36.5 g/mol
Mass = 7.2 * 36.5 = 262.8 g
Answer:1.34 ×10^-5
Explanation:
AgCl = (Ag+) (Cl-)
=(S)(S)
= S²
S stands for molar solubility
Ksp =S² = 1.80 × 10^ -10
S= √[1.80 × 10^ -10]
=1.34 × 10^-5