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Leokris [45]
3 years ago
11

Calculate the molar solubility of AgCl, using its Ksp value of 1.8 x 10-10.

Chemistry
1 answer:
qwelly [4]3 years ago
8 0

Answer:1.34 ×10^-5

Explanation:

AgCl = (Ag+) (Cl-)

=(S)(S)

= S²

S stands for molar solubility

Ksp =S² = 1.80 × 10^ -10

S= √[1.80 × 10^ -10]

=1.34 × 10^-5

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