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mixer [17]
3 years ago
10

Which element will most easily lose an electron? A. Calcium (Ca) B. Potassium (K) C. Boron (B) D. Krypton (Kr)

Chemistry
2 answers:
Artemon [7]3 years ago
8 0
<h2>Answer:</h2>

Option B. Potassium(K).

<h2>Explanation:</h2>

Electronic configuration of the given elements are:

  1. Ca - [Ar] 4s²
  2. K - [Ar] 4s¹
  3. B - [He] 2s2 2p1
  4. Kr -  [Ar] 3d¹⁰4s²4p⁶
  1. Krypton(K) have 36 electrons and it is a noble gas and hence all of its shells are completely filled with electrons and hence it will never loose electrons in normal conditions.
  2. Boron(B) have 5 electrons and 3 electrons in its outer shell. In order to attain a stable configuration it will loose 3 electrons and it is difficult to loose 3 electrons at a time for an atom.
  3. Calcium(Ca) have 20 electrons and 2 electrons in its outermost shell, in order to attain a stable configuration it will loose 2 electrons. it is quite difficult but easier than Boron.
  4. Potassium(K) have 21 electrons and 1 electron in its outermost orbit and in order to attain a stable configuration it will loose 1 electron. It is much easier to donate 1 electron than 2 or 3 electrons.

Result: Potassium will loose an electron most easily from the given elements.

geniusboy [140]3 years ago
6 0

Answer:

Potassium

Explanation:

Answer via Educere/ Founder's Education

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Explanation:

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8 0
2 years ago
The variety of organisms within an ecosystem is characteristic of which type of diversity?
a_sh-v [17]

Answer:

c. Species diversity

Explanation:

Because is talking about of organisms, it means, living beings and they are classified like species. There are species of animals and plants

7 0
3 years ago
Read 2 more answers
A gas occupies 3.00 L at standard temperature. The volume at 350 C is 6.84 L.<br> True <br> False
kupik [55]

Answer:

TRUE

Explanation:

Standard temperature is 273K and 350°C is 623K.

V/V' = T/T'

3/6.84 = 273/T'

T' = (273×6.84)/3

=> T' = 623K

So it is true.

7 0
3 years ago
A 9.03 g sample of magnesium reacts completely with 3.48 g of nitrogen to form a compound of
hjlf

Answer:

12.5 g

Explanation:

<em>12.5 g of the compound would be formed.</em>

First, let us look at the balanced equation of reaction.

3 Mg(s) + N_2(g) --> Mg_3N_2(s)

3 moles of Mg is required to react with 1 mole of N2 to produce 1 mole of product.

<em>Recall that: mole = mass/molar mass</em>

9.03 g of Mg = 9.03/24.3 = 0.3716 mole

3.48 g of N2 = 3.48/28 = 0.1243 mole

Mole ratio of Mg/N2 = 3:1

<em>Hence, there is no limiting reactant.</em>

3 moles of Mg is required for 1 mole of product.

0.3716 mole of Mg will therefore require:

       0.3716 x 1/3 = 0.1239 moles of product.

Molar mass of product Mg_3N_2 = 100.9 g/mol

Mass of 0.1239 mole Mg_3N_2 = mole x molar mass

                      = 0.1239 x 100.9 = 12.5 g

8 0
3 years ago
A sample of 4.0 L of nitrogen, at 1.2 atmospheres, is transferred to a 12 L container.
Zielflug [23.3K]

Answer:

The pressure will be 0.4 atm.

Explanation:

The gas laws are a set of chemical and physical laws that allow determining the behavior of gases in a closed system. The parameters evaluated in these laws are pressure, volume, temperature and moles.

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them less times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:

"The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

P*V= k

If you initially have the gas at a volume V1 and press P1, when the conditions change to a volume V2 and pressure P2, the following is satisfied:

P1*V1= P2*V2

In this case:

  • P1= 1.2 atm
  • V1= 4 L
  • P2= ?
  • V2= 12 L

Replacing:

1.2 atm* 4 L= P2* 12 L

Solving:

P2=\frac{1.2 atm*4 L}{12 L}

P2= 0.4 atm

<u><em>The pressure will be 0.4 atm.</em></u>

7 0
3 years ago
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