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2 years ago

8

There are instructions and the problem please help asap! Find out if it is linear or proportional or both and solve create equat

ion.

1 answer:

likoan [24]2 years ago

5 0

Its linear because it dose not hit 0,0 and the graph cant simply

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BRAINLIEST AND EXTRA POINTS! ANY FAKE ANSWERS WILL BE REPORTED! 1. Write a completely simplified rational expression that repres

balandron [24]

Answer:

You did not give a amount for how much Salma has.

Step-by-step explanation:

8 0

1 year ago

!*I NEED HELP AND QUICK*!

rewona [7]

1)96/8=12
2)(95*6+5)/6 : (24+1)/3 = (95*6+5)/6 : 2*25/6 = 575/6 *6/50=575/50
=23/2=11 1/2
11 1/2

3) (11 1/2)*12 area of the one type of the wall, there are 2 such walls
(11 1/2)*12*2
(8 1/3)*12 area of the second type of the wall, there are 2 such walls
(8 1/3)*12 *2

Altogether area of the walls:
(11 1/2)*12*2 + (8 1/3)*12 *2=12*2(11 1/2 + 8 1/3)= =24(19+3/6+2/6)=24(19+5/6) = 456 +24*(5/6)= 456+20= 476

Tamara needs total 476 square feet, which is less than 480 square feet, so she has enough paint.

5 0

3 years ago

At a pet store, 3/8 of the total animals were dogs. of those dogs 2/7 were labrador dogs. what fraction of the total pets were l

9966 [12]

Answer: 3/28

Step-by-step explanation:

Here we go, whenever you see the word "of" this mean to multiply

2/7 x 3/8 = 3/28

Answer: 3/28 .

I hope this help...

7 0

2 years ago

From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s

Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

60 out of 100 scores are passing scores, hence $n = 100, \pi = \frac{60}{100} = 0.6$

95% confidence level

So $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7$

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

The lower limit is 0.5.
The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

5 0

2 years ago

I guess u have to find the area

Nesterboy [21]

18
Because 6•3= 18
Hope this helped

7 0

2 years ago

Read 2 more answers