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3 years ago

I NEED TO WRITE AN ARTICLE ON PHOTOPIC, MESOPIC AND SCOTOPIC VISION MEASUREMENTS

1 answer:

7 0

That right there gives you three terms that you can search online.
I tried it just now, and there was one place that even compared
photopic and mesopic to each other in the same article. Try it.
You'll have your information faster than I could type it for you.

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Cho các máy cắt sử dụng trong công nghiệp có ký hiệu trên nhãn thiết bị: C350; B500. Hãy tính dòng điện bảo vệ ngắn mạch và dòng

solniwko [45]

Answer:

ask in the English then I can help you

Explanation:

please mark me as brain list

3 0

3 years ago

The total pressure inside a 1.43 L cylinder at 28C is 1.03 atm. If the temperatures drops to -35C, and the volume remains the sa

Art [367]

Answer:

0.81452 atm

Explanation:

$P_1$ = Initial pressure = 1.43 L

$V_1=V_2$ = Volume

$T_1$ = Initial temperature = (28+273.15) K

$T_2$ = Final temperature = (-35+273.15) K

$P_2$ = Final pressure

From the ideal gas law we have

$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow P_2=\dfrac{P_1V_1T_2}{T_2V_2}\\\Rightarrow P_2=\dfrac{1.03\times 1.43\times (273.15-35)}{(273.15+28)1.43}\\\Rightarrow P_2=0.81452\ atm$

The pressure in the cylinder is 0.81452 atm

8 0

3 years ago

A 2130 kg car is parked on a hill that makes a 15º angle with the horizontal. What is the normal force on the car?

valentinak56 [21]

Answer:

20573.67N

Explanation:

Given;

mass (m) of the car = 2130kg

angle of inclination Θ = 15⁰

The normal force (F) on the car is given by

F = mgcosΘ

where g is the acceleration due to gravity.

Taking g as 10 $m/s^{2}$ and substituting the values of m and Θ into the equation. We have;

F = 2130 x 10 x cos 15⁰

F = 2130 x 10 x 0.9659

F = 20573.67N

Therefore the normal force on the car is 20573.67N

7 0

4 years ago

A switch in an electric circuit controls the flow of electrons in the circuit.

Delvig [45]

Answer:

when you switch off an electrical curcuit you tend to create a 'break' in the curcuit,preventing the electric current to flow around the curcuit,this can be caused by a simple switch or 'break'

Explanation:

7 0

3 years ago

A volleyball is hit upward with an initial velocity of 6.0 m/s. Calculate the displacement of the volleyball when its final velo

Nimfa-mama [501]

Answer:

1.78 m upward

Explanation:

We can find the displacement of the volleyball by using the SUVAT equation:

$v^2 - u^2 = 2ad$

where, assuming upward as positive direction:

u = 6.0 m/s is the initial velocity

v = 1.1 m/s is the final velocity

a = g = -9.8 m/s^2 is the acceleration of gravity

d is the displacement

Solving the equation for d, we find:

$d=\frac{v^2-u^2}{2a}=\frac{1.1^2-6.0^2}{2(-9.8)}=1.78 m$

And since it is positive, the displacement is upward.

5 0

3 years ago