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lianna [129]
3 years ago
5

I NEED TO WRITE AN ARTICLE ON PHOTOPIC, MESOPIC AND SCOTOPIC VISION MEASUREMENTS

Physics
1 answer:
lapo4ka [179]3 years ago
7 0
That right there gives you three terms that you can search online.
I tried it just now, and there was one place that even compared
photopic and mesopic to each other in the same article.  Try it.
You'll have your information faster than I could type it for you.
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What is a solvent and a solute
artcher [175]

Answer:

solvent: the substance in which a solute dissolves to produce a homogeneous mixture. solute: the substance that dissolves in a solvent to produce a homogeneous mixture.

Explanation:

eSo basically  thats  aswer

7 0
3 years ago
How does a blue object look under all colors of light
OverLord2011 [107]
The "blue" object would look the same. Say that this blue object is a square. That "square" is every color but blue. The only reason that you see it as "blue" is because what we call "blue", it the only color of light that bounces back at our eyes. Under all colors of light, especially simultaneously. This square or any shape for that matter would absorb the other colors of light, but the blue will be rejected. Therefore, we can only see what bounces back at our eyes, which is the color blue in this case. 

Hope this helps, WyattMarine501
6 0
3 years ago
What is the purpose of having a phone?
Rus_ich [418]

Answer:

The cellphone's main purpose is to keep people connected, regardless of the distance that separates them. Cellphones, much like traditional phones, allow you to place and receive calls.

Explanation:

8 0
3 years ago
Calculate the acceleration of a bus that speed up from 20ms-1 to 40ms-1 in 8 seconds?​
Anastaziya [24]

Answer:

2.5 ms^-2

Explanation:

acceleration

= (final velocity - initial velocity)/time

= [(40m/s) - (20m/s)]/8s

= (20m/s)/8s

= 5/2 m/s²

= 2.5 m/s²

= 2.5 ms^-2

3 0
3 years ago
The electric field at the distance of 3.5 meters from an infinite wall of charges is 125 N/C. What is the magnitude of the elect
RideAnS [48]

Explanation:

It is given that,

Distance, r = 3.5 m

Electric field due to an infinite wall of charges, E = 125 N/C

We need to find the electric field 1.5 meters from the wall, r' = 1.5 m. Let it is equal to E'. For an infinite wall of charge the electric field is given by :

E=\dfrac{\lambda}{2\pi \epsilon_o r}

It is clear that the electric field is inversely proportional to the distance. So,

\dfrac{E}{E'}=\dfrac{r'}{r}

E'=\dfrac{Er}{r'}

E'=\dfrac{125\times 3.5}{1.5}  

E' = 291.67 N/C

So, the magnitude of the electric field 1.5 meters from the wall is 291.67 N/C. Hence, this is the required solution.

5 0
4 years ago
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