Question

Please Help!!!! ASAP!!!

Answer 1

Answer:

$0.594 m/s^2$

Explanation:

The acceleration is the derivative of the velocity. Therefore, we need to differentiate each component of the velocity to find the components of the acceleration first.

The velocity along the x-axis is:

$v_x = 5.00 - 0.0170 t^2$

Differentiating,

$a_x = -2(0.0180)t = -0.0360 t$

Similarly, the velocity along the y-axis is:

$v_y = 2.00 + 0.550 t$

Differentiating,

$a_y = +0.550$

So now we have the components of the acceleration; substituting t = 6.23 s, we get:

$a_x = -0.0360 (6.23)=0.224 m/s^2\\a_y = 0.550 m/s^2$

And so the magnitude of the acceleration is

$a=\sqrt{a_x^2+a_y^2}=\sqrt{(0.224)^2+(0.550)^2}=0.594 m/s^2$