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kondor19780726 [428]
3 years ago
14

A scuba diver shines a flashlight from beneath the surface of water (n = 1.33 such that the light strikes the water-air boundary

with an angle of incidence of 37°. at what angle is the beam refracted?
Physics
1 answer:
Len [333]3 years ago
7 0
The beam is refracted at 53.17-degree angle (asin 0.800414 = 53.17-degree). This problem can be solved by using the Snell's Law which described the refracted beam angle which traveled through a different media, in this case, through water and air. The formula of Snell's Law is stated as n1 sin θ1= n2 sin θ2. In this formula n1 is the refraction index of medium 1, θ1 is the normal light angle in the medium 1, n2 is the refraction index of medium 2, and θ2 is the normal light angle in the medium 2<span>. </span>
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A driver entering the outskirts of a city takes her foot off the accelerator so that the car slows down from 90 km/h to 50 km/h
Varvara68 [4.7K]

Answer:

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5 0
2 years ago
How to do this, i'm completely lost
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You need to figure out t4 to know the tension in the string.

Since the whole thing is not moving t1 + t2 + t3 = t4.

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t1 =3.2 * 44g 
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t4 = t1 + t2 + t3 = 5570,118

The t4 also is given by:

t4 = r * T * sin Ф

r = 7
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T = t4 / (r * sinФ)

T = t4 / (7 * sin(32°)) 

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This question relates to the practicality of searching for intelligent life in other solar systems by detecting their radio broa
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