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sergeinik [125]
3 years ago
7

Can someone please provide a step by step explanation to the question in the image? It is really important for me to understand

these questions. Thanks in advance!​

Physics
1 answer:
Sergio039 [100]3 years ago
3 0

Answer:

21.21 N @ 81.87°

Explanation:

Divide each force into horizontal components and vertical components.

F₁ is in the +x direction, so F₁ₓ = 12 N and F₁ᵧ = 0 N.

F₂ is in the +y direction, so F₂ₓ = 0 N and F₂ᵧ = 9 N.

F₃ is 53.13° above the -x axis.  So the components are:

F₃ₓ = -15 cos (53.13°) = -9 N

F₃ᵧ = 15 sin (53.13°) = 12 N

The horizontal component of the resultant force is the sum of the horizontal components of the individual forces:

Fₓ = F₁ₓ + F₂ₓ + F₃ₓ

Fₓ = 12 N + 0 N + (-9 N)

Fₓ = 3 N

Similarly, the vertical component of the resultant force is the sum of the vertical components of the individual forces:

Fᵧ = F₁ᵧ + F₂ᵧ + F₃ᵧ

Fᵧ = 0 N + 9 N + 12 N

Fᵧ = 21 N

To find the magnitude of the resultant force, use Pythagorean theorem:

F² = Fₓ² + Fᵧ²

F² = (3 N)² + (21 N)²

F = 21.21 N

To find the direction relative to the +x axis, use trigonometry:

tan θ = Fᵧ / Fₓ

tan θ = (21 N) / (3 N)

θ = 81.87°

The resultant force is 21.21 N at a angle of 81.87° above the +x axis (round as needed).

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Answer:

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Explanation:

Data obtained from the question include:

Acceleration (a) = 26ft/s2

Distance (s) = 256ft

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A. Determination of the time taken for the car to stop.

Let us obtain an express for time (t)

Acceleration (a) = Velocity (V)/time(t)

a = V/t

Velocity (V) = distance (s) /time (t)

V = s/t

a = s/t^2

Cross multiply

a x t^2 = s

Divide both side by a

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Take the square root of both side

t = √(s/a)

Now we can obtain the time as follow

Acceleration (a) = 26ft/s2

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Time (t) =..?

t = √(s/a)

t = √(256/26)

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Therefore, the time taken for the car to stop is 3.14 secs

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V = U + at

Final velocity (V) = 0

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Time (t) = 3.14 sec

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From third equation of motion we know that v^2=u^2+2as

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a=-3.2m/sec^2

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Here metal lead is having an oxidation state of +4 called as Pb^{4+} cation and sulphur non metal has oxidation state of -2 called as S^{2-}. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral PbS_2

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