Answer:
Explanation:
From the information given:
Mass of carbon tetrachloride = 5 kg
Pressure = 1 bar
The given density for carbon tetrachloride = 1590 kg/m³
The specific heat of carbon tetrachloride = 0.84 kJ/kg K
From the composition, the initial volume of carbon tetrachloride will be:
= 0.0031 m³
Suppose is independent of temperature while pressure is constant;
Then:
The change in volume can be expressed as:
However; the workdone = -PdV
W = - 7.6 J
The heat energy Q = Δ h
Q = 84 kJ
The internal energy is calculated by using the 1st law of thermodynamics; which can be expressed as;
ΔU = ΔQ + W
ΔU = 84 kJ + ( -7.6 × 10⁻³ kJ)
ΔU = 83.992 kJ
Non-living molecules.
Hope it helps! :)
Answer : The volume of NaOH stock solution used should be, 250 ml
Solution :
According to the neutralization law,
where,
= molarity of NaOH solution = 0.50 M
= volume of NaOH solution = 3.0 L
= molarity of NaOH stock solution = 6.0 M
= volume of NaOH stock solution = ?
Now put all the given values in the above law, we get the volume of NaOH stock solution.
(1 L = 1000 ml)
Therefore, the volume of NaOH stock solution used should be, 250 ml