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Vsevolod [243]
3 years ago
10

Why does water boil at 100°C and methane boil at -161°C Please help me

Chemistry
1 answer:
Crank3 years ago
3 0

Explanation:

The main difference in boiling points are due to intermolecular attractions. With water, it is a polar molecule, has hydrogen bonding, and exhibits london forces. All of these combined, make H2O bonds very strong, which means more energy is required to transition from one state to another, leading to higher boiling points.

On the other hand, methane is a non-polar molecule that only exhibits very weak london forces. It being a non-polar molecule, means its bonds are very weak, which means less energy is required to boil methane.

Also, the Celsius system was made so that water would be a reference. This is a reason for why its boiling point temperature is convenient

You might be interested in
Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A soluti
ella [17]

Answer :

The mass of excess mass of Na_2CO_3, AgNO_3,Ag_2CO_3\text{ and }NaNO_3 are, 1.908 g, 0 g, 12.144 g and 3.74 g respectively.

Explanation : Given,

Mass of Na_2CO_3 = 4.25 g

Mass of AgNO_3 = 7.50 g

Molar mass of Na_2CO_3 = 106 g/mole

Molar mass of AgNO_3 = 170 g/mole

Molar mass of Ag_2CO_3 = 276 g/mole

Molar mass of NaNO_3 = 85 g/mole

First we have to calculate the moles of Na_2CO_3 and AgNO_3.

\text{Moles of }Na_2CO_3=\frac{\text{Mass of }Na_2CO_3}{\text{Molar mass of }Na_2CO_3}=\frac{4.25g}{106g/mole}=0.040moles

\text{Moles of }AgNO_3=\frac{\text{Mass of }AgNO_3}{\text{Molar mass of }AgNO_3}=\frac{7.50g}{170g/mole}=0.044moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction is,

Na_2CO_3+2AgNO_3\rightarrow Ag_2CO_3+2NaNO_3

From the balanced reaction we conclude that

As, 2 moles of AgNO_3 react with 1 mole of Na_2CO_3

So, 0.044 moles of AgNO_3 react with \frac{0.044}{2}=0.022 moles of Na_2CO_3

From this we conclude that, Na_2CO_3 is an excess reagent because the given moles are greater than the required moles and AgNO_3 is a limiting reagent and it limits the formation of product.

The excess mole of Na_2CO_3 = 0.040 - 0.022 = 0.018 mole

Now we have to calculate the mass of excess mole of Na_2CO_3.

\text{Mass of }Na_2CO_3=\text{Moles of }Na_2CO_3\times \text{Molar mass of }Na_2CO_3=(0.018mole)\times (106g/mole)=1.908g

Now we have to calculate the moles of Ag_2CO_3.

As, 1 moles of AgNO_3 react to give 1 moles of Ag_2CO_3

So, 0.044 moles of AgNO_3 react to give 0.044 moles of Ag_2CO_3

Now we have to calculate the mass of AgCO_3.

\text{Mass of }Ag_2CO_3=\text{Moles of }Ag_2CO_3\times \text{Molar mass of }Ag_2CO_3=(0.044mole)\times (276g/mole)=12.144g

Now we have to calculate the moles of NaNO_3.

As, 2 moles of AgNO_3 react to give 2 moles of NaNO_3

So, 0.044 moles of AgNO_3 react to give 0.044 moles of NaNO_3

Now we have to calculate the mass of NaNO_3.

\text{Mass of }NaNO_3=\text{Moles of }NaNO_3\times \text{Molar mass of }NaNO_3=(0.044mole)\times (85g/mole)=3.74g

6 0
4 years ago
Please Helppppp:(((((
kozerog [31]

Answer:

do we add???

Explanation:

6 0
3 years ago
Read 2 more answers
1. What is the maximum amount of NaCl that can dissolve in
Sergio [31]

Answer:

70g

Explanation:

Rate = 35g of NaCl can dissolve in 100g of H2O

Use proportions for 200g of H2O:

\frac{35}{100} = \frac{x}{200}

Since 200 is double of 100, x needs to be double of 35.

\frac{35}{100} = \frac{70}{200}

Therefore the maximum amount of NaCl that can dissolve in 200g of water is 70g.

6 0
3 years ago
What is the empirical formula for a compound if a sample contains 1.0 g of S and 1.5 g of O?
sammy [17]
I think it’s SO3 I’m not quite sure though
6 0
2 years ago
6 moles of H2O is equal to how many molecules?
bagirrra123 [75]
A mole is equal to 6.02x10^23, so one mole of H2O has 6.02x10^23 water molecules. To get how many of them are in 6 moles you need to multiple it by six:
(6.02x10^23)x6= 3.612x10^24
So, there’s 3.612x10^24 water molecules in 6 moles of water
4 0
3 years ago
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