Answer:
Colorado Springs , Colorado , United States
The mercury (Hg) has 80 electrons. The electrons are distributed in the s, p, d and f orbitals. The electronic configuration of Hg can be shown as-. We can see that there are two filled d-orbitals 3d and 4d. There is only one filled f orbital which is 4f. The electron cloud of the s, p, d and f are different due to their different screening and penetration effect towards the nucleus. The electron cloud of f-orbital is most diffuse than the other three. The outermost electrons of mercury is , which is its valence electrons i.e. (+2).
<span>1.16 moles/liter
The equation for freezing point depression in an ideal solution is
ΔTF = KF * b * i
where
ΔTF = depression in freezing point, defined as TF (pure) ⒠TF (solution). So in this case ΔTF = 2.15
KF = cryoscopic constant of the solvent (given as 1.86 âc/m)
b = molality of solute
i = van 't Hoff factor (number of ions of solute produced per molecule of solute). For glucose, that will be 1.
Solving for b, we get
ΔTF = KF * b * i
ΔTF/KF = b * i
ΔTF/(KF*i) = b
And substuting known values.
ΔTF/(KF*i) = b
2.15âc/(1.86âc/m * 1) = b
2.15/(1.86 1/m) = b
1.155913978 m = b
So the molarity of the solution is 1.16 moles/liter to 3 significant figures.</span>
I think it’s the second one
Answer:
They are malleable because of the drifting electrons and because the cations slide easily past each other. Metal is malleable because its atoms can slide over each other without damaging its structure.