Answer:
not sure but does it say line UW are common or shared
Step-by-step explanation:
Answer:
1/15
Step-by-step explanation:
Ms. Fox loves to eat cereal and she notices that she only has 1/3 of the box of cereal left. If she spread that amount across 5 days, how much cereal will she have for each day?
The amount of cereal she would have per day is calculated as:
5 days = 1/3 of the box
1 day = x
Cross Multiply
5 days × x = 1 day × 1/3 of the box
x = 1/3 ÷ 5
x = 1/3 × 1/5
x = 1/15 of the box
Probability = (number of ways to succeed) / (total possible outcomes) .
The total possible results of rolling two dice is
(6 on the first cube) x (6 on the second one) = 36 possibilities.
How many are successful ? I need you to clarify something first.
You said that the 'second die' shows an odd number. When a pair
of dice is rolled, the problem usually doesn't distinguish between them.
And in fact, you said that they're "tossed together" (like a spinach and
arugula salad ?) so I would understand that they would lose their identity
unless they were, say, painted different colors, and we wouldn't know
which one is the second one.
Oh well, I'll just work it both ways:
First way:
Two identical dice are tossed.
The total is 5 and ONE cube shows an odd number.
How can that happen ?
1 ... 4
4 ... 1
3 ... 2
2 ... 3
Four possibilities. Probability = 4/36 = 1/9 = 11.1% .
=======================================
Second way:
A black and a white cube are tossed together.
The total is 5 and the white cube shows an odd number.
How can that happen:
B ... W
4 .... 1
2 .... 3
Only two possibilities. Probability = 2/36 = 1/18 = 5.6% .
Answer:
a) 

b) 

c) For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower
d)
(a)
Solving for n we got:
(b)
And replacing the info we have:

Step-by-step explanation:
Part a
For this case we have the following data given
represent the sample mean for the customer order totals
represent the population deviation
represent the sample size selected
The confidence level is 90% or 0.90 and the significance level would be
and
and the critical value from the normal standard distirbution would be given by:

And the confidence interval is given by:

And replacing we got:


Part b
The sample size is now n = 75, but the same confidence so the new interval would be:


Part c
For this case when we increase the sample size the margin of error would be lower and then the interval would be narrower
Part d
The margin of error is given by:
(a)
Solving for n we got:
(b)
And replacing the info we have:

1,995 for each game.
1,995+1,995=3,990
3,990+295=4,285.00