The length of a rectangle is three times as long as its width. The width of this rectangle is 6 inches smaller than its length.
Find the length and the width. (It would also be interesting to know its area and perimeter!)
1 answer:
Answer:
The length is 9in and the width is 3in
The perimeter is 24in and the area is 27in²
Step-by-step explanation:
To start we have to make 2 equations with the information that gave us the problem
l = length
w = width
w = l - 6in
l = 3w
we replace l in the first equation with (3w)
w = (3w) - 6in
w - 3w = -6in
-2w = -6in
w = -6in / (-2)
w = 3in
now we replace the value of w in the second equation
l = 3w
l = 3 (3in)
l = 9in
Now that we have the length and width we can calculate the perimeter and the area with the following formulas
p = perimeter
a = area
p = 2w + 2h
p = 2(3in) + 2(9in)
p = 6in + 18in
p = 24in
a = w * l
a = 3in * 9in
a = 27in²
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