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denpristay [2]
3 years ago
11

28. Samuel applies a horizontal force of 35.0 N to a sleigh over a distance of 1.50 m

Physics
1 answer:
solong [7]3 years ago
5 0

Answer:

Explanation:

The formula you use is

W = F * d

F = 35.0 N

d = 1.5 m

W = 35 N * 1.5 m

W = 52.5 J (oules)

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What is the difference between temperature and heat???
olga55 [171]

Answer:

Difference between heat and temperature in tabular form

Heat vs Temperature

1.Heat is a form of energy that can transfer from a hot body to a cold body. and Temperature is the degree of hotness and coldness of a body.

2.Heat is the total kinetic energy and potential energy obtained by molecules in an object. and Temperature is the average K.E of molecules in a substance.

3.Heat flows from hot body to cold body. It rises when heated and falls down when an object is cooled down and It has a working ability. It does not have the working ability

.

4.Its SI unit is “Joule” and Its SI unit is “Kelvin”.

5.It is measured by the calorimeter and It is measured by the thermometer

.

6.It is represented by “Q”. and It is represented by “T”.

Explanation:

A calorimeter is an object used for calorimetry, or the process of measuring the heat of chemical reactions or physical changes as well as heat capacity. ... A simple calorimeter just consists of a thermometer attached to a metal container full of water suspended above a combustion chamber.

8 0
3 years ago
How does an object's acceleration change if the net
topjm [15]
C.the acceleration is doubled
5 0
2 years ago
How do you get 5 minutes to seconds
sergiy2304 [10]
There are 60 seconds in a minute.

This means that 5 minutes would be 60 times 5.
60×5 = 300

There are 300 seconds in 5 minutes.
5 0
3 years ago
Read 2 more answers
3) A tolley of mass 4kg, moving with a velocity
Leokris [45]

Answer:

3.57 m/s

Explanation:

The sum of the 2 momentums Is equal the finale momentums. so if momentums Is q, v Is velocity and m Is Mass, q3=m1*v1+m2**v2=16+9=25 m*kg/s

q3=m3*v3

v3=q3/m3=25/(4+3)=3.57m/s

8 0
3 years ago
The maximum Compton shift in wavelength occurs when a photon isscattered through 180^\circ .
vlabodo [156]

Answer: 90\°

Explanation:

The Compton Shift \Delta \lambda in wavelength when the photons are scattered is given by the following equation:

\Delta \lambda=\lambda_{c}(1-cos\theta)     (1)

Where:

\lambda_{c}=2.43(10)^{-12} m is a constant whose value is given by \frac{h}{m_{e}c}, being h the Planck constant, m_{e} the mass of the electron and c the speed of light in vacuum.

\theta) the angle between incident phhoton and the scatered photon.

We are told the maximum Compton shift in wavelength occurs when a photon isscattered through 180\°:

\Delta \lambda_{max}=\lambda_{c}(1-cos(180\°))     (2)

\Delta \lambda_{max}=\lambda_{c}(1-(-1))    

\Delta \lambda_{max}=2\lambda_{c}     (3)

Now, let's find the angle that will produce a fourth of this maximum value found in (3):

\frac{1}{4}\Delta \lambda_{max}=\frac{1}{4}2\lambda_{c}(1-cos\theta)      (4)

\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}(1-cos\theta)      (5)

If we want \frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}, 1-cos\theta   must be equal to 1:

1-cos\theta=1   (6)

Finding \theta:

1-1=cos\theta

0=cos\theta  

\theta=cos^{-1} (0)  

Finally:

\theta=90\°    This is the scattering angle that will produce \frac{1}{4}\Delta \lambda_{max}      

7 0
3 years ago
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