1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Neporo4naja [7]
3 years ago
11

IPDE stands for ____________. A. Identify, Predict, Decide, and Execute B. Interpret, Predict, Divide, and Execute C. Identify,

Predict, Deal, and Emergency D. Identify, Predict, Determine, and Execute
Physics
2 answers:
jeyben [28]3 years ago
6 0

Answer:

A. Identify, Predict, Decide, and Execute

Explanation:

Identify, Predict, Decide, and Execute (IPDE) is an acronym for the process behind the principles of defensive driving and complexities of visual perception in traffic. It is very useful at the time of driving to keep the calm and in order to avoid driving accidents. One way to learn this acronym is to put it in practice every time you are driving.

Arturiano [62]3 years ago
5 0
<span>d.Identify Predict Decide Execute hope this helps:)</span>
You might be interested in
A man is standing on a weighing machine on a ship which is bobbing up and down with simple harmonic motion of period T=15.0s.Ass
STALIN [3.7K]

Well, first of all, one who is sufficiently educated to deal with solving
this exercise is also sufficiently well informed to know that a weighing
machine, or "scale", should not be calibrated in units of "kg" ... a unit
of mass, not force.  We know that the man's mass doesn't change,
and the spectre of a readout in kg that is oscillating is totally bogus.

If the mass of the man standing on the weighing machine is 60kg, then
on level, dry land on Earth, or on the deck of a ship in calm seas on Earth,
the weighing machine will display his weight as  588 newtons  or as 
132.3 pounds.  That's also the reading as the deck of the ship executes
simple harmonic motion, at the points where the vertical acceleration is zero.

If the deck of the ship is bobbing vertically in simple harmonic motion with
amplitude of M and period of 15 sec, then its vertical position is 

                                     y(t) = y₀ + M sin(2π t/15) .

The vertical speed of the deck is     y'(t) = M (2π/15) cos(2π t/15)

and its vertical acceleration is          y''(t) = - (2πM/15) (2π/15) sin(2π t/15)

                                                                = - (4 π² M / 15²)  sin(2π t/15)

                                                                = - 0.1755 M sin(2π t/15) .

There's the important number ... the  0.1755 M.
That's the peak acceleration.
From here, the problem is a piece-o-cake.

The net vertical force on the intrepid sailor ... the guy standing on the
bathroom scale out on the deck of the ship that's "bobbing" on the
high seas ... is (the force of gravity) + (the force causing him to 'bob'
harmonically with peak acceleration of  0.1755 x amplitude).

At the instant of peak acceleration, the weighing machine thinks that
the load upon it is a mass of  65kg, when in reality it's only  60kg.
The weight of 60kg = 588 newtons.
The weight of 65kg = 637 newtons.
The scale has to push on him with an extra (637 - 588) = 49 newtons
in order to accelerate him faster than gravity.

Now I'm going to wave my hands in the air a bit:

Apparent weight = (apparent mass) x (real acceleration of gravity)

(Apparent mass) = (65/60) = 1.08333 x real mass.

Apparent 'gravity' = 1.08333 x real acceleration of gravity.

The increase ... the 0.08333 ... is the 'extra' acceleration that's due to
the bobbing of the deck.

                        0.08333 G  =  0.1755 M

The 'M' is what we need to find.

Divide each side by  0.1755 :          M = (0.08333 / 0.1755) G

'G' = 9.0 m/s²
                                       M = (0.08333 / 0.1755) (9.8) =  4.65 meters .

That result fills me with an overwhelming sense of no-confidence.
But I'm in my office, supposedly working, so I must leave it to others
to analyze my work and point out its many flaws.
In any case, my conscience is clear ... I do feel that I've put in a good
5-points-worth of work on this problem, even if the answer is wrong .

8 0
3 years ago
Calculate the acceleration of a 270000-kg jumbo jet just before takeoff when the thrust on the aircraft is 160000 N .
Radda [10]

Answer:

<h3>The answer is 0.59 m/s²</h3>

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

a =  \frac{f}{m}  \\

f is the force

m is the mass

From the question we have

a =  \frac{160000}{270000}  =  \frac{16}{27}  \\  = 0.592592...

We have the final answer as

<h3>0.59 m/s²</h3>

Hope this helps you

7 0
3 years ago
An object at rest cannot remain at rest unless which of the following holds?View Available Hint(s)An object at rest cannot remai
Leni [432]

Answer:

True The net force must be zero for the acceleration to be zero

Explanation:

In order to analyze the statements of this problem we propose your solution.

First let's look at Newton's first, which stable that every object is at rest or with constant speed unless something takes it out of this state (acceleration)

Now let's look at the second postulate, which says that force is related to the product of the mass of a body and its acceleration.

As a result of these two laws, for a body is a constant velocity the summation force on it must be zero.

Now we can analyze the statements given.

True The net force must be zero for the acceleration to be zero

False. If the force is different from zero, there is acceleration that changes the speeds

False. There may be forces, but the sum of them must be zero

False. If a force acts, the acceleration is different from zero and the speed changes

5 0
3 years ago
Look at this picture of a whale shark. Which question about the whale shark is nonscientific?
Sergeeva-Olga [200]

I need the picture to answer the question

5 0
3 years ago
Read 2 more answers
Heather drops a ball weighing 0.50kg a distance of 2.0m. If the speed of the ball right after it bounces is the same speed of th
ki77a [65]
The speed of the ball just before impact was v=√(2gh) = 6.26m/s.  The acceleration is twice this over the time (twice because the second speed is the same in the other direction, meaning the total change in speed is 2V)
a = 12.52/0.10 = 125.2m/s²
The force is F=ma, so F = 0.5kg·125.2m/s² = 62.6N
7 0
3 years ago
Other questions:
  • Does the ke of a car change more when it accelerates from 11 km/h to 21 km/h or when it accelerates from 21 km/h to 31 km/h?
    11·1 answer
  • What effect does Earth’s spherical shape have on the amount of sunlight that reaches the equator?
    14·1 answer
  • Another name for a period is a family?
    14·1 answer
  • Match the term to its definition.
    15·2 answers
  • Two technicians are discussing headlights. Technician A says that the electricity creates electromagnetic energy in the filament
    6·1 answer
  • Gravity is a force between any two objects with mass wht doesn’t a person feel a gravitational force between them herself and an
    5·1 answer
  • Okay I better get a good answer for this guy I'm puttin' all my money on it.
    9·2 answers
  • PLEASE HEELP!!!
    5·1 answer
  • Using complete sentences and your own words describe some of the ways humans use water.
    7·1 answer
  • Newton’s law of gravity says the gravitational force between two objects is proportional to:
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!