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Zanzabum
2 years ago
11

Good evening! Can someone please answer this, ill give you brainliest and your earning 50 points. Would be very appreciated.

Physics
2 answers:
Paul [167]2 years ago
6 0

Drinking-Water - Direct

Eating Habits - Direct

Washing Clothes - Indirect

Gekata [30.6K]2 years ago
4 0
Drinking Water - Direct
Our Eating Habits - Direct
Washing Clothes - Indirect
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A very large sheet of a conductor carries a uniform charge density of on its surfaces. What is the electric field strength 3.00
olga55 [171]

Complete Question

A very large sheet of a conductor carries a uniform charge density of 4.00\  pC/mm^2  on its surfaces. What is the electric field strength 3.00 mm outside the surface of the conductor?

Answer:

The electric field is  E  =  4.5198 *10^{5} \ N/C

Explanation:

From the question we are told that

    The charge density is  \sigma  =  4.00pC  /mm^2 = 4.00 * 10^{-12 } *  10^{6} = 4.00 *10^{-6}C/m

    The position outside the surface is  a  =  3.00 \ mm  =  0.003 \ m

   

Generally the electric field is mathematically represented as

          E  =  \frac{\sigma}{\epsilon _o  }

Where  \epsilon_o is  the permitivity of free space with values  \epsilon _o  = 8.85 *10^{-12}  F/m

substituting values  

           E  =  \frac{4.0*10^{-6}}{8.85 *10^{-12}  }

           E  =  4.5198 *10^{5} \ N/C

5 0
3 years ago
How many watt hoves are there in 895g of matter?
polet [3.4K]

Answer:

1.16 hp

Explanation:

7 0
3 years ago
A weightlifter completes a series of lifts with a 700 N weight. In one lift, he raises the weight to a height of 2.5 m off the g
zhannawk [14.2K]

Answer:

The output power the weightlifter is 2916.67 W.

Explanation:

Given;

weight lifted, W = 700 N

height the weight is lifted, h = 2.5 m

time taken to lift the weight, t = 0.60 s

The output power the weightlifter is calculated as;

Power = Energy applied / time taken

Energy applied = weight lifted x height the weight is lifted

Energy applied = 700 x 2.5

Energy applied = 1750 J

Power = 1750 / 0.6

Power = 2916.67 J/s = 2916.67 W.

Therefore, the output power the weightlifter is 2916.67 W.

5 0
3 years ago
If a dice is thrown at random find the probability of getting 4​
Brrunno [24]

Answer:

☆<《<em><u>HOPE IT WILL HELP YOU</u></em><em><u> </u></em>》>☆

Explanation:

The probability of getting 4 is 1

8 0
3 years ago
Read 2 more answers
Zorn and Porsha are ice skating. Porsha has a mass of 60 kg, and Zorn has a mass of 40 kg. As they face each
algol13

Assuming the friction between the skaters and the ice is  negligible, the magnitude of Porsha's acceleration is 2.8m/s².

Missing part of the question: determine the magnitude of Porsha's acceleration.

Given the data in the question;

  • Mass of Porsha; m_{porsha} = 60kg
  • Mass of Zorn; m_{zorn} = 40kg
  • Force of Porsha push; F_{porsha} = 168N

Magnitude of Porsha's acceleration; a = \ ?

To determine the magnitude of Porsha's acceleration, we use Newton's second laws of motion:

F = m*a

Where m is the mass of the object and a is the acceleration.

We substitute the mass of Porsha and the force he used into the equation

168N = 60kg * a\\\\a = \frac{168kg.m/s^2}{60kg}\\\\a = 2.8m/s^2

Therefore, assuming the friction between the skaters and the ice is  negligible, the magnitude of Porsha's acceleration is 2.8m/s².

Learn more: brainly.com/question/25125444

3 0
3 years ago
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