The total kinetic energy of the system after collision is 223.5J
In elastic collision kinetic energy and momentum are conserved.
According to the question
mass of object a = 25kg
mass of object b = 25 kg
initial velocity of a u1 = 5.98 m/s
initial velocity of b u2 = 0
so from momentum conservation-
mau1 + mbu2 = (m1+m2)v
25kg × 5.98m/s + 25×0 = (25+25)v
v = 2.99 m/s
Now the total kinetic energy after the collision will be:
final kinetic energy = 1/2 (m1+m2) v²
= 1/2 (25+25)× (2.99)²
= 223.5 J
Thus, total kinetic energy of the system after collision is 223.5J
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Answer: a) electric field will be zero at zero meters apart
b) for smaller charge q, E = 6.048X10^6N/m towards away from the charge,
for bigger charge Q, E = 4.032X10^6N/m
Explanation:
Detailed explanation and calculation is shown in the image below.
Answer:
b. $96,914
Explanation:
360-day borrowing rate = 5%
spot rate = 0.48
360-day deposit rate = 6%
Borrow at the rate of 5% to get
SF200,000/1.05 = $190,476.19
Convert at the spot rate of $0.48 to get
190,476.19*0.48 = $91,428.57
Invest at the interest rate of 6% to get
91,428.57/1.06 = 96,914.28
Therefore, Parker Company will receive $96,914 in 360 days.
Answer:
P = 79993.43245
Explanation:
Được -
Vị trí tâm ống dẫn dưới đường thuỷ ngân h1 = 820 mm
Chênh lệch chiều cao của cột thủy ngân h2 = 880mm
Tỷ trọng của thủy ngân = 13,5951 g / cm3
P = mật độ * gia tốc do trọng lực a * h
Thay thế các giá trị đã cho, chúng ta nhận được -
P = 13,5951 g / cm3 * 980,665 cm / s2 * (88-82) cm
P = 79993.43245
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