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Zanzabum
2 years ago
11

Good evening! Can someone please answer this, ill give you brainliest and your earning 50 points. Would be very appreciated.

Physics
2 answers:
Paul [167]2 years ago
6 0

Drinking-Water - Direct

Eating Habits - Direct

Washing Clothes - Indirect

Gekata [30.6K]2 years ago
4 0
Drinking Water - Direct
Our Eating Habits - Direct
Washing Clothes - Indirect
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Water enters an ice machine at 55F and leaves as ice at 25F. If the COP of the ice machine is 3.7 during this operation, determi
boyakko [2]

Answer:

The required power is P_i = 0.2692 \ hp

Explanation:

From the question we are told that

   The temperature of the water entering ice machine is T_1 =  55 ^o F

    The temperature of the water leaving is T_2 = 25 ^oF

    The COP of the ice machine is COP= 3.7

    The production rate of an ice  \r m = 15.0 \ lbm /hr

    The energy that needs to removed from each lbm of water at 55 F is E = 169 Btu

Generally the cooling load of the ice machine is mathematically represented as

       \r Q_L =  \r m * E

      \r Q_L =15 * 169

=>  \r Q_L = 2535 \ Btu/h

Generally the COP of the ice machine is mathematically represented as

       COP =  \frac{\r Q_L}{P_i}

Here P_i is the net power  input needed to successfully run the ice machine

So  

     3.7 =  \frac{2535}{P_i}

=>   P_i = 685 \  Btu/h

Converting to horsepower

      P_i = \frac{685}{2545}

=>   P_i = 0.2692 \ hp

     

3 0
3 years ago
Solve P= a+b+c for B
Dahasolnce [82]

Answer:

b = - a - c + p

Explanation:

P= a+b+c : move the b over to the other side.

-b + p = a + c : move p over the other side.

-b = a + c - p : now just convert the a + c - p into,

b = -a - c + p

8 0
3 years ago
HELPP!!
lisov135 [29]

Answer:

1.2 MPS

Explanation:

8 0
3 years ago
Which of the following is an example of acceleration? I. A car speeds up. II. A car slows down. III. A car travels in a straight
svetlana [45]
I., II., and IV. are examples of acceleration. III. isn't.
6 0
4 years ago
A sealed test tube traps 25.0 cm3 of air at a pressure of 1.00 atm and temperature of 18°C. The test tube’s stopper has a diamet
puteri [66]

Answer:

180° C

Explanation:

First we start by finding the area of the stopper.

A = πd²/4, where d = 1.5 cm = 0.015 m

A = 3.142 * 0.015² * ¼

A = 1.767*10^-4 m²

Next we find the force on the stopper

F = (P - P•)A, where

F = 10 N

P = pressure inside the tube,

P• = 1 atm

10 = (P - 101325) * 1.767*10^-4

P - 101325 = 10/1.767*10^-4

P - 101325 = 56593

P = 56593 + 101325

P = 157918 Pascal

Now, remember, in an ideal gas,

P1V1/T1 = P2V2/T2, where V is constant, then we have

P1/T1 = P2/T2, and when we substitute the values, we have

101325/(273 + 18) = 157918/ T2

101325/291 = 157918/ T2

T2 = (157918 * 291)/101325

T2 = 453 K

T2 = 453 - 273 = 180° C

3 0
4 years ago
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