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11111nata11111 [884]
3 years ago
12

while driving his sports car at 20.0 m/s down a four lane highway, eddie comes up behind a slow moving dump truck and decides to

pass it in the left hand lane. of eddie can accelerate at 5.00 m/s^2, how long will it take for him to reach a speed of 30.0 m/s
Physics
1 answer:
Arte-miy333 [17]3 years ago
3 0

Explanation:

Given:

u = 20 m/s

a = 5 m/s^2

v = 30 m/s

t = ?

Use the first kinematic equation of motion:

v = u + at

t = (v - u)/a = 10/5 = 2 seconds

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Are passing through optical Centre deviate why ​
nikklg [1K]

Answer:

Actually the same happens when the ray passes through optical centre. This can be observed in a thick lens. In thin lenses the perpendicular distance between extended incident ray and extended emergent ray is negligible. So we can say that light ray passes through optical centre without deviation.

Explanation:

7 0
3 years ago
Lauren is comparing rocks from two different locations. She has the following
telo118 [61]

Answer:

the same type because they both formed from rock material.

Explanation:

4 0
3 years ago
. A water balloon is thrown horizontally at a speed of 2.00 m/s from the roof of a building that is 6.00m above the ground. At t
dedylja [7]

Answer:

Explanation:

Height of building

H = 6m

Horizontal speed of first balloon

U1x = 2m/s

Second ballot is thrown straight downward at a speed of

U2y = 2m/s

Time each gallon hits the ground

Balloon 1.

Using equation of free fall

H = Uoy•t + ½gt²

Uox = 0 since the body does not have vertical component of velocity

6 = ½ × 9.8t²

6 = 4.9t²

t² = 6 / 4.9

t² = 1.224

t = √1.224

t = 1.11 seconds

For second balloon

H = Uoy•t + ½gt²

6 = 2t + ½ × 9.8t²

6 = 2t + 4.9t²

4.9t² + 2t —6 = 0

Using formula method to solve the quadratic equation

Check attachment

From the solution we see that,

t = 0.9211 and t = -1.329

We will discard the negative value of time since time can't be negative here

So the second balloon get to the ground after t ≈ 0.92 seconds

Conclusion

The water ballon that was thrown straight down at 2.00 m/s hits the ground first by 1.11 s - 0.92s = 0.19 s.

4 0
3 years ago
Read 2 more answers
A concert loudspeaker suspended high off the ground emits 28.0 W of sound power. A small microphone with a 0.700 cm2 area is 55.
grandymaker [24]

Explanation:

It is known that wave intensity is the power to area ratio.

Mathematically,    I = \frac{P}{A}

As it is given that power is 28.0 W and area is 7 \times 10^{-5} m^{2}.

Therefore, sound intensity will be calculated as follows.

             I = \frac{P}{A}

               = \frac{28.0 W}{4 \times 3.14 \times 7 \times 10^{-5} m^{2}}

                = 0.318 \times 10^{5} W/m^{2}

or,             = 3.18 \times 10^{4} W/m^{2}

Thus, we can conclude that sound intensity at the position of the microphone is 3.18 \times 10^{4} W/m^{2}.

7 0
3 years ago
A body accelerate uniformly from rest at 2m/s square.Calculate its velocity after traveling 9m
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The correct answer for this question is 6m/s. I hope this helps.
5 0
3 years ago
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