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11111nata11111 [884]
3 years ago
12

while driving his sports car at 20.0 m/s down a four lane highway, eddie comes up behind a slow moving dump truck and decides to

pass it in the left hand lane. of eddie can accelerate at 5.00 m/s^2, how long will it take for him to reach a speed of 30.0 m/s
Physics
1 answer:
Arte-miy333 [17]3 years ago
3 0

Explanation:

Given:

u = 20 m/s

a = 5 m/s^2

v = 30 m/s

t = ?

Use the first kinematic equation of motion:

v = u + at

t = (v - u)/a = 10/5 = 2 seconds

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A mass weighing 4 lb stretches a spring 2 in. Suppose that the mass is given an additional 6-in displacement in the positive dir
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Answer:

\frac{1}{8} y'' + 2y' + 24y=0

Explanation:

The standard form of the 2nd order differential equation governing the motion of mass-spring system is given by

my'' + \zeta y' + ky=0

Where m is the mass, ζ is the damping constant, and k is the spring constant.

The spring constant k can be found by

w - kL=0

mg - kL=0

4 - k\frac{1}{6}=0

k = 4\times 6 =24

The damping constant can be found by

F = -\zeta y'

6 = 3\zeta

\zeta = \frac{6}{3} = 2

Finally, the mass m can be found by

w = 4

mg=4

m = \frac{4}{g}

Where g is approximately 32 ft/s²

m = \frac{4}{32} = \frac{1}{8}

Therefore, the required differential equation is

my'' + \zeta y' + ky=0

\frac{1}{8} y'' + 2y' + 24y=0

The initial position is

y(0) = \frac{1}{2}

The initial velocity is

y'(0) = 0

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