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Rudiy27
3 years ago
15

Explain how you could write 35% as the sum of two benchmark percents or as a multiple of a percent.

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
7 0
<span><u>Possible correct answers</u> are:

20%+15%; and 50% of 70%.

Explanation<span>:

Benchmark percents are percents that are commonly used. 20% and 15% are two commonly used percentages; the sum of them would be
20%+15% = 35%.

A multiple of a percent is a percent of a percent. Taking 50% of 70% of a number is the same as multiplying by 0.5(0.7) = 0.35.</span></span>
makkiz [27]3 years ago
7 0
Best Answer : you would have to divide 35 with the place value it is in. For example : 35% ; 35/100 and then you divide which is 0.35, that is your answer. As a fraction 0.35 is really 7/20.
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PLEASE HURRY <br> What is the measure of M?<br> 52<br> Р<br> 78°<br> M
vodomira [7]

Answer:

50 degree

Step-by-step explanation:

the angle sum property of the equilateral triangle is =180 degree

since, 52 degree +78 degree +x =180 degree

130 degree + x =180 degree

x= (180-130) degree

<h3> x= 50 degree</h3>

hope this helps you out

4 0
2 years ago
Why is it valid to say that both a function and its inverse describe the same relationship
liberstina [14]
A comparison between a function and its inverse would show that the domain and range of the original function swap. The domain of the function becomes the range of the inverse, the range of the function becomes the domain of its inverse. 

Looking at ordered pairs of the function and its inverse would look like this:

(2,4) on the original function becomes (4,2) on the inverse. 

While the graph of a function and its inverse are noticeably different an important thing to note is that it is merely a reflection across the line y=x. 

So even though they appear different you are looking at the same relationship just as y vs. x instead of x vs. y
4 0
3 years ago
The change in water level of a lake is modeled by a polynomial function, W(x). Describe how to find the x-intercepts of W(x) and
Agata [3.3K]
<span>First. <u>Finding the x-intercepts of </u>W(x)
</span><span>
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To find the zeros of the polynomial:

f(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+...+a_{2}x^{2}+a_{1}x+a_{0}

We use the Trial-and-Error Method which states that a factor of the constant term:

a_{0}

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So let's use an example: Suppose you have the following polynomial:

W(x)=x^{4}-x^{3}-7x^{2}+x+6

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</span>W(1)=0 \\ W(-1)=0 \\ W(2)=-12 \\ W(-2)=0 \\ W(3)=0 \\ W(-3)=48 \\ W(6)=840 \\ W(-6)=1260<span>

From the foregoing, we can affirm that 1, -1, -2 \ and \ 3 are zeros of the polynomial.

</span>Second. <u>Construction a rough graph of</u> W(x)

Given that this is a polynomial, then the function is continuous. To graph it we set the roots on the coordinate system. We take the interval:

[-2,-1]

and compute W(c) where c is a real number between -2 and -1. If W(c)>0, the curve start rising, if not, the curve start falling. For instance:

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Therefore the curve start falling and it goes up and down until x=3 and from this point it rises without a bound as shown in the figure below


7 0
3 years ago
Read 2 more answers
If mn, solve for x.<br> (3x + 9) (x + 21)
Sloan [31]

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3 years ago
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stich3 [128]

Answer:

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