Answer:

Explanation:
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In this case, since vaporization is the processes by which a liquid goes to the gas phase, fusion by which a solid goes to liquid and deposition by which a gas goes to solid; we infer that the following set up relates the enthalpies associated to each process:

Because deposition goes from a state with more energy to a state with less energy, therefore it is negative; in such a way, by plugging in we obtain:

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I don't know what you are asking but AC= Alternative current
V= Volt
Answer:
A) Concentration
Explanation:
When you add a chemical to itself it becomes more concentrated making it more powerful and faster
Answer:
-2, -1, 0, +1, +2
Explanation:
The quantum numbers describe the quantum state of an electron in an atom. These numbers are symbolized as n, l, m, and s. There are rules for the combination of these numbers. The angular quantum number (ℓ) is related to the magnetic number (<em>m</em>): if ℓ is equal to a number a, thus <em>m</em> can be any integer number between - a and +a.
According to this rule:
If ℓ = 2, thus <em>m</em> can be have a value of an integer between -2 and +2 ⇒ -2, -1, 0, +1, +2
Answer:
0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.
Explanation:
The balanced reaction is:
Na₂CO₃ + 2 HCl → 2 NaCl + CO₂ + H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of each compound participate in the reaction:
- Na₂CO₃: 1 mole
- HCl: 2 moles
- NaCl: 2 moles
- CO₂: 1 mole
- H₂O: 1 mole
On the other hand, Avogadro's Number is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole. Avogadro's number applies to any substance.
In this case, you can apply the following rule of three: if 6.023*10²³ molecules of Na₂CO₃ are contained in 1 mole, 1.67*10²² molecules will be contained in how many moles?

amount of moles= 0.0277 moles
In this case, you can apply the following rule of three: if by stoichiometry 1 mole of Na₂CO₃ produces 2 moles of NaCl, 0.0277 moles of Na₂CO₃ will produce how many moles of NaCl?

amount of moles of NaCl= 0.0554 moles
<u><em>0.0554 moles of NaCl are produced from the reaction of 1.67*10²² molecules of Na₂CO₃ with excess HCl.</em></u>