Answer : The equilibrium concentration of is, 1.0 M
Explanation : Given,
Equilibrium concentration of = 0.26 M
Volume of solution = 1.00 L
Equilibrium constant = 4.0
The balanced equilibrium reaction will be,
The expression of equilibrium constant for the reaction will be:
From the reaction we conclude that the concentration of and are equal.
Let the concentration of be 'X'.
So, concentration of = X
Now put all the values in this expression, we get :
Thus,
The concentration of at equilibrium = X = 1.0 M
The concentration of at equilibrium = X = 1.0 M
It looks like we are solving for a pressure. All that is required is some algebraic manipulation to find our pressure in mmHg.
Given:
(5.0 m³)(7.5 mmHg) = (P)(4.0m³)
Multiply:
37.5 = 4.0P
Divide:
9.375 = P
P = 9.4 mmHg (remember sig figs)
<h3>
Answer:</h3>
9.4 mmHg
Answer:
magnitude of electric field E = 45 × 10³ N/C
Explanation:
given data
magnitude of the charge is q = 5.00 μC = 5 × C
distance = 1 m
to find out
magnitude of the electric field
solution
we will apply here magnitude of electric field formula that is
magnitude of electric field E = k × .......................1
put here value we get
magnitude of electric field E = 9 × ×
magnitude of electric field E = 45 × 10³ N/C
Answer:
cThe answer is chimical reaction
If the trend is linear, that is boiling point increases by a constant amount for each additional saturated carbon, the boiling point of octane would be 69*2 because you are adding two saturated carbons. So the predicted boiling point is 138C, which is very close to the literature value