Answer:
E'=(3/16)E
Explanation:
The electric field generated by a Van de Graff generator can be taken as the electric field generated by a hollow shell (for distance out of the shell):
Q: electric charge
K: Coulomb's constant
R: distance in which E is measured.
If the distance is increased to R'=2R, and the charge to Q'=(4/3)Q the new electric field is:
hence, the new electric field E' is 3/16 times the previous electric field E
Answer:
a) 0 m/s
b) - 24 m/s
c) - 68 m
Explanation:
Given:
Initial distance = - 4 m
Initial velocity, u = 4 m/s
1) acceleration, a = - 2 m/s² for time, t = 2 seconds
thus,
velocity after 2 seconds will be
from Newton's equation of motion
v = u + at
v = 4 + (-2) × 2
v = 0 m/s
2) Velocity after 2 second is the initial velocity for this case
given acceleration = - 6 m/s² for 4 seconds
thus,
final velocity, v = 0 + ( - 6 ) × 4 = - 24 m/s
here the negative sign depicts the velocity in opposite direction to the initial direction of motion
thus, velocity after 6 seconds = - 24 m/s
3) Now,
Total displacement in 6 seconds
= Displacement in 2 seconds + Displacement in 4 seconds
From Newton's equation of motion
where,
s is the distance
u is the initial speed
a is the acceleration
t is the time
thus,
= +
= - 16 - 48
= - 64 m
Hence, the final displacement = - 64 - 4 = - 68 m
Answer:
1. Yes, it can occur adiabatically.
2. The work required is: 86.4kJ
Explanation:
1. The internal energy of a gas is just function of its temperature, and the temperature changes between the states, so, the internal energy must change, but how could it be possible without heat transfer? This process may occur adiabatically due to the energy balance:
This balance tell us that the internal energy changes may occur due to work that, in this case, si done over the system.
2. An internal energy change of a gas may be calculated as:
Assuming constant,