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3 years ago

How do you find the acceleration of an object?

2 answers:

4 0

Rearrange the equation F = ma to solve for acceleration. You can change this formula around to solve for acceleration by dividing both sides by the mass, so: a = F/m. To find the acceleration, simply divide the force by the mass of the object being accelerated.

Hope i helped :)

erica [24]3 years ago

4 0

Answer:

$\large \boxed{{\displaystyle A=\frac{V_f-V_i}{t}}}$

Explanation:

$\displaystyle acceleration = \frac{change \ in \ velocity }{elapsed \ time}$

$\displaystyle A=\frac{V_f-V_i}{t}$

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Does the same battery always deliver the same amount of flow to any circuit? Mention two observations of any circuits in this la

V125BC [204]

Answer:

Yes

Explanation:

Given that the battery is the same the PD ( potential difference ) in the circuit will also be the same likewise the flow of charge in the circuit,

Hence the same amount of charge flow is delivered to any circuit.

attached below are examples

6 0

3 years ago

What is biasing and doping

Flura [38]

Answer:

Biasing - Biasing means being unfair to someone or something, and liking the other one or helping them.

Doping - Doping is where a person use drug to get better at sporting and get stronger muscles, such as getting stronger, getting faster and so on. It is mostly used by athletics.

5 0

2 years ago

Read 2 more answers

One jet is flying east at 880 km/h,and another is traveling north at 880 km/h.Do they have the same velocity?the same speed?Expl

shusha [124]

Velocity is the speed and direction combined.
So, the two jets both are going at the same speed.
But they are going in different directions, so their velocities are different.

6 0

2 years ago

A cat dozes on a stationary merry-go-round, at a radius of 4.6 m from the center of the ride. then the operator turns on the rid

ioda

Radius = 4.6 m
Time for one complete rotation t = 5.5 s.
Distance = 2 x 3.14 x R = 2 x 3.14 x 4.6 m = 28.888.
Velocity V = distance / time = 28.888 / 5.5 s = 5.25 m/s
Force exerted by cat Fc = mV^2 / R = (mx 5.25^2) / 4.6 m
Force of the cat Fc = 6m, m being the mass.
Normal force = Us x m x g = Us x m x 9.81 = Us9.81m
equating the both forces => Us9.81m = 6m => Us = 6 / 9.81 => Us = 0.6116 So coefficient of static friction = 0.6116

4 0

2 years ago

A sealed test tube traps 25.0 cm3 of air at a pressure of 1.00 atm and temperature of 18°C. The test tube’s stopper has a diamet

puteri [66]

Answer:

180° C

Explanation:

First we start by finding the area of the stopper.

A = πd²/4, where d = 1.5 cm = 0.015 m

A = 3.142 * 0.015² * ¼

A = 1.767*10^-4 m²

Next we find the force on the stopper

F = (P - P•)A, where

F = 10 N

P = pressure inside the tube,

P• = 1 atm

10 = (P - 101325) * 1.767*10^-4

P - 101325 = 10/1.767*10^-4

P - 101325 = 56593

P = 56593 + 101325

P = 157918 Pascal

Now, remember, in an ideal gas,

P1V1/T1 = P2V2/T2, where V is constant, then we have

P1/T1 = P2/T2, and when we substitute the values, we have

101325/(273 + 18) = 157918/ T2

101325/291 = 157918/ T2

T2 = (157918 * 291)/101325

T2 = 453 K

T2 = 453 - 273 = 180° C

3 0

3 years ago