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kkurt [141]
3 years ago
6

Can y'all help me with my math problem please

Mathematics
1 answer:
ololo11 [35]3 years ago
8 0
• 2 x 10^5 = $200,000
• $200,000 * 8 years = $1,600,000
• $1,600,000 = 1.6 x 10^6
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Quizizz help 10 pts each brainiest guaranteed blah blah blah
emmainna [20.7K]

Answer:

5x^3-2x^2+2x+9

Step-by-step explanation:

(5x^3+4x^2)−(6x^2−2x−9)

To find the opposite of 6x^2−2x−9 find the opposite of each term.

5x^3+4x^2−6x^2+2x+9

Combine 4x^2 and 6x^2 to get −2x^2.

5x^3-2x^2+2x+9

5 0
3 years ago
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What’s 12 1/6 converted into a decimal
My name is Ann [436]

Answer:

12.167

Step-by-step explanation:

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3 years ago
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You Stupid whats 9+10
devlian [24]

Answer: 19 booooooooooiii


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3 years ago
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I will give brainliest to the first person who answers.
nasty-shy [4]

Answer:

the answer is \sqrt{5\\} , and - \sqrt{5\\} which is C.

Step-by-step explanation:

well I got that answer by doing this

we have x^{2}= 5

For x^{2}= f (a) the solutions are x = \sqrt{f(a)\\} , - \sqrt{f(a)\\}

so in this case the solutions are \sqrt{5\\}, and - \sqrt{5\\}

HOPE THIS HELPS :)

3 0
3 years ago
Find the margin of error for a 90% confidence interval when the standard deviation is LaTeX: \sigma= 50????=50 and LaTeX: n = 25
Murrr4er [49]

Answer:

The margin of error  for a 90% confidence interval is 16.4

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 25

Standard deviation = 50

z_{critical}\text{ at}~\alpha_{0.10} = \pm 1.64

Margin of error =

z_{critical}\times \dfrac{\sigma}{\sqrt{n}}

Putting the values, we get,

1.64\times \dfrac{50}{\sqrt{25}} = 16.4

Thus, the margin of error  for a 90% confidence interval is 16.4

8 0
3 years ago
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