The second choice. Intersects means cuts the y axis. And if you go to -infinity (figuratively speaking! lol) x^3 dominates and goes to -infinity, way down, the other way for infinity

4 0

3 years ago

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Complete the following statement of congruence: MON~= .

AlexFokin [52]

Answer:

C. RTS

Step-by-step explanation:

When two triangles are congruent, they will have congruent vertices, like each vertex has a partner.

Take a look at the shape of the triangle.

If you look at the triangle on the right, you can see it is almost like a right triangle.

"R" is at the right angle. "S" is on the short side and "T" is on the long side.

In the triangle on the left, "M" is at the right angle. "N" is on the short side and "O" is on the long side.

Thus, the pairs of congruent angles are:

M ≅ R

O ≅ T

N ≅ S

When you write the statement of congruence between triangles, order the letters by their congruent pair.

MON ≅ RTS

8 0

3 years ago

H E L P PLZZZ !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Kitty [74]

Answer:

138

Step-by-step explanation:

just plug in the numbers:

4*6^2 - 36/6

use pemdas

4*36 - 6 = 144-6 = 138

7 0

2 years ago

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Find the area of the shaded region. Round the the nearest tenth.

Brums [2.3K]

Answer:

226.084 sq.m.

Step-by-step explanation:

Radius of circle = 18.6 cm

Area of sector = $\frac{\theta}{360^{\circ} }\pi r^2$

Area of sector = $\frac{123}{360} \times 3.14 \times (18.6)^2$

Area of sector = $371.157 m^2$

Area of triangle = $\frac{1}{2} \times a \times b \times Sin x$

a = OA = radius = 18.6 cm

b = OB = radius = 18.6 cm

x =123 °

Substitute the values in the formula

Area of triangle = $\frac{1}{2} \times 18.6 \times 18.6 \times Sin 123$

Area of triangle = $145.073 m^2$

So, Area of shaded region = Area of sector - Area of triangle

= $371.157 m^2-145.073 m^2$

= $226.084 m^2$

Hence the area of the shaded region is 226.084 sq.m.

5 0

3 years ago