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4 years ago

Who is one woman who has contributed greatly to science? How?

1 answer:

8 0

Marie Curie was the first woman to receive a Nobel Prize in Physics and became the first person to receive a second Nobel Prize in Chemistry

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Which types of waves requires matter to carry energy?

fredd [130]

Answer:

Mechanical waves

7 0

3 years ago

The position of an object that is oscillating on a spring is given by the equation x = (17.4 cm) cos[(5.46 s-1)t]. what is the a

bulgar [2K]

The angular frequency of this motion is 5.46 rad/s.

The oscillation of spring is an example of Simple Harmonic Motion(SHM).

The general equation of an SHM is given by the formula.

X = Acos(wt)

Here A is the amplitude

ω is the angular frequency

T is the time

Comparing the above equation with the given condition,

X = 17.4 cm cos(5.46t)

A = 17.4 cm

ω = 5.46 rad/s

T = 1 s

Hence, the angular frequency of this motion is 5.46 rad/s.

To know more about the "general equation of SHM", refer to the link below:

brainly.com/question/14869852?referrer=searchResults

#SPJ4

6 0

2 years ago

g If you keep the launch angle fixed, but double the initial launch speed, what happens to the range?

kiruha [24]

Answer:

Range will become 4 times of initial range

Explanation:

Let the velocity of projection is u

And angle at which projectile is projected is $\Theta$

And acceleration due to gravity is $g\ m/sec^2$

So range of projectile is equal to $R=\frac{u^2sin2\Theta }{g}$ ........eqn 1

Now in second case it is given that velocity of launching is doubled

So new velocity $u_{new}=2u$

So new range will be equal to $R_{new}=\frac{(2u)^2sin2\Theta }{g}=\frac{4u^2sin2\Theta }{g}$ .....eqn 2

Now dividing eqn 2 by eqn 1

$\frac{R_{new}}{R}=\frac{4u^2sin2\Theta }{g}\times \frac{g}{u^2sin2\Theta }$

$R_{new}=4R$

So if we double the initial launch speed then range will become 4 times

4 0

4 years ago

A construction worker drives to his work 43 km away at an average speed of 62 km/h. Before he gets out of his car he realizes he

swat32

Answer:

Explanation:

243w4e5drftgyhuj

7 0

3 years ago

Chase is trying to push a 120-kilogram boulder along the street. He applies a force of 1,115 newtons, and he does this over a di

lord [1]

Answer:

The work done is equal to zero = 0

Explanation:

Let us remember that the definition of physical work is given by the product of force by the displacement of the body.

$Work=F*d\\\\where\\F= force [N]\\d=distance [m]\\replacing\\Work=1115*(0) = 0$

4 0

3 years ago