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ss7ja [257]
3 years ago
10

Keesha did an experiment to study the rate of photosynthesis in the water plant Elodea. She placed a piece of Elodea in a beaker

of water and set the beaker 10 centimeters (cm) from a light source. Keesha counted the bubbles released from the plant every minute for five minutes (min). She repeated the process two more times. First, she moved the light to 20 cm from the beaker, and then she moved the light to 30 cm from the beaker. What is the outcome variable (dependent variable) in this experiment? What is the key phrase that tells you what you are looking for?
Physics
1 answer:
KIM [24]3 years ago
6 0

What is the outcome variable in this experiment?

The dependent variable which is the outcome of bubbles produced.

Keesha did an experiment to study the rate of photosynthesis in the water plant Elodea.

My guess would be that since we initially know what the experiment is for, the key phrase is:

Keesha counted the bubbles released from the plant every minute for five minutes (min). She repeated the process two more times.

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Answer:

t = 12.82s

Explanation:

F = m×a

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29 = 1/2×(2)×t^2

t^2 = 29s

t = 5.39s

and attains the velocity of:

v = a×t

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Then,to cover the last x = 80 m with a speed of 10.77 m/s in time:

t = x/v

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Therefore, it will take the sprinter 7.43 + 5.39 = 12.82s

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Answer:

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"copernicus demonstrated that the earth was not the center of the solar system. we now know that our solar system is not the cen
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If you lose control of your vehicle and collide with a fixed object, such as a tree, at 60 m.p.h., the force of impact is the sa
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