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Margaret [11]
3 years ago
6

Amplitude of superposition of two waves y1 = 5sinwt and y2 = 5coswt is

Physics
1 answer:
liq [111]3 years ago
5 0

Answer:

correct answer is a

Explanation:

For this exercise we must add the two oscillations

          y_total = y₁ + y₂

          y_total = 5 sin wt + 5 cos wt

          y _total = 5 (sin t wt + cos wt)

the sine and cosine functions are related

          cos (a +90) = cos a cos 90 - sin 90 sin a = - sin a

let's call  

        a= wt

let's substitute

           y_total = 5 (-cos (wt +90) + cos wt)

the cosine function has the same value for +θ and -θ

           cos θ = cos (-θ)

Thus

           y_total = 0

correct answer is a

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\texttt{ }

<h3>Further explanation</h3>

Let's recall Elastic Potential Energy formula as follows:

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<u>Given:</u>

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\texttt{ }

<em>Next , we will use </em><em>Conservation of Energy</em><em> formula to solve this problem:</em>

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Ek = \frac{1}{2}k ( (x')^2 - x^2 ) + mgh

Ek = \frac{1}{2}(445 \frac{5}{11}) ( 0.0460^2 - 0.0275^2 ) + 1.25(9.8)(0.0735)

\boxed {Ek \approx 1.20 \texttt{ J}}

\texttt{ }

<h3>Learn more</h3>
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\texttt{ }

<h3>Answer details</h3>

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