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3 years ago

Calculate the time (in seconds) needed for a car to accelerating from 0 m/s to 10 m/s at 5 m/s^2?

Physics

1 answer:

bazaltina [42]3 years ago

4 0

Answer: 2 s

Explanation: In order to solve this problem we have to use the formule of the final speed getting with a constant acceleration, it is given by;

Vfinal=Vo+a*t where Vo is zero.

so then t=Vfinal/a = (10 m/s)/5 m/s^2= 2 s

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an apple in a tree has a gravitational potential energy of 175J and a mass of 0.36g . how high from the ground is the apple

Neko [114]

The equation for potential energy is denoted as;

Pe = mgh,

where m = the mass, g = acceleration due to gravity, and h = vertical height of the apple. We are given the units for everything but height, which is also what we are solving for. We can then algebraically rearrange our initial equation to solve for h;

h = (Pe)/(mg)

Plug in your given units, and solve!

Post-check:

h = Pe/mg

h = 175J/(0.36g)(-9.81m/s^2)

h = appr. 49.5 meters

Note: Potential energy is a vector quantity; the displacement of the apple will be a negative number, but the distance itself, a scalar quantity, will be the absolute value of that.

5 0

3 years ago

You are driving home from school steadily at for 180 km. It then begins to rain and you slow to You arrive home after driving 4.

nata0808 [166]

Answer:

Explanation:

Question is incomplete

Assuming the question you have asked is

You are driving home from school steadily at 95 km/h for 180 km. It then begins to rain and you slow to 65 km/h. You arrive home after driving 4.5 h.

given,

speed of 95 km/h for 180 km

due to rain

speed is reduced to 65 km/h

distance traveled in 4.5 hour

time taken to travel 180 km

d = s x t

$t = \dfrac{180}{95}$

t = 1.9 hr

distance traveled in time, t' = 4.5-1.9 = 2.6 hr

Speed of vehicle = 65 Km/h

d' = s x t'

d' = 65 x 2.6

d'= 169 Km

total distance your hometown from school

D = d + d'

D = 180 + 169

D = 349 Km

6 0

3 years ago

A ball is projected horizontally from the top of a bertical building 25.0m above the ground level with an initial velocity of 8.

kirill115 [55]

Answer:

Solution given:

height [H]=25m

initial velocity [u]=8.25m/s

g=9.8m/s

now;

a. How long is the ball in flight before striking the ground?

Time of flight =?

Now

Time of flight= $\sqrt{\frac{2H}{g}}$

substituting value

= $\sqrt{\frac{2*25}{9.8}}$
=2.26seconds

<h3>the ball is in flight before striking the ground for 2.26seconds.</h3>

b. How far from the building does the ball strike the ground?

Horizontal range=?

we have

Horizontal range=u* $\sqrt{\frac{2H}{g}}$

=8.25*2.26
=18.63m

<h3>The ball strikes 18.63m far from building. </h3>

7 0

3 years ago

Identify the three types of isometric transformations. A. reflection, rotation, translation B. reflection, rotation, dilation C.

inessss [21]

reflection, rotation, translation

4 0

3 years ago

Absolute differences between each observed mass and the accepted value,divided by the accepted value, multiplied by 100%

timama [110]

Answer:

The percentage error e% = Δm/m 100

Explanation:

The absolute error is the assessment with which measurements are made, it is given by the minimum reading value of a given instrument.

The accepted value is the value measured in an instrument. Or the one calculated by an experiment.

The percentage error is the ratio of the absolute error between the value of the average per 100

e% = Δm/m 100

3 0

3 years ago