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3 years ago

During the day, Susan notices that the wind is blowing onshore at the beach. What is this called?

2 answers:

6 0

For the answer to the question above, it is A. Sea Breeze or on shore, breeze is a gentle wind blowing from the sea toward land, that develops over bodies of water near land due to differences in air pressure created by their different heat capacity. It is a common occurrence along coasts during the morning as solar radiation heats the land more quickly than the water.

spin [16.1K]3 years ago

6 0

A) just took test please make brainiliest

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Two gratings A and B have slit separations dA and dB, respectively. They are used with the same light and the same observation s

77julia77 [94]

Answer:

a) dB / dA = 2 ,

b) Network B Network A

2 1

4 2

6 3

Explanation:

a) The expression for grating diffraction is

d sin θ = m λ

where d the distance between two slits, λ the wavelength and m an integer that represents the diffraction range

In this exercise we are told that the two spectra are in the same position, let's write the expression for each network

Network A

m = 1

sin θ = 1 λ / dA

Network B

m = 2

sin θ = 2 λ / dB

they ask us for the relationship between the distances, we match the equations

λ / dA) = 2 λ / dB

dB / dA = 2

b) let's write the equation of the networks

sin θ = m_A λ / dA

sin θ = m_B λ / dB

we equalize

m_A λ/ dA = m_B λ / dB

we use that

dB / dA = 2

m_A 2 = m_B

therefore the overlapping orders are

Network B Network A

2 1

4 2

6 3

4 0

3 years ago

If a particle with a charge of +4.3 × 10−18 C is attracted to another particle by a force of 6.5 × 10−8 N, what is the magnitude

Mrrafil [7]

The magnitude of the electric field at this location is $1.5\times 10^{10} N/C$

Explanation:

Given

$Charge\ of\ the\ particle\ Q=4.3\times 10^-18\ C\\Force\ with\ which\ it\ is\ attracted\ F=6.5\times 10^-8\ N$

Electric field at this location determined by the force and charge.

E=F/Q

$E=\frac{6.5\times 10^-8}{4.3\times10^-18} =1.5\times\ 10^{10} \ N/C$

7 0

4 years ago

A merry-go-round is spinning at a rate of 4.04.0 revolutions per minute. Cora is sitting 0.50.5 m from the center of the merry-g

dsp73

Answer:

angular speed of both the children will be same

Explanation:

Rate of revolution of the merry go round is given as

f = 4.04 rev/min

so here we have

$f = \frac{4.04}{60} =0.067 rev/s$

here we know that angular frequency is given as

$\omega = 2\pi f$

$\omega = 2\pi(0.067)$

$\omega = 0.42 rad/s$

now this is the angular speed of the disc and this speed will remain same for all points lying on the disc

Angular speed do not depends on the distance from the center but it will be same for all positions of the disc

7 0

3 years ago

In the ballistic pendulum experiment (A.K.A conservation of momentum & energy), the velocity of the projectile was measured

Fed [463]

Answer: The combined velocity = 0.413m/a

Maximum angle Ø = 54.7

Explanation: Please find the attached files for the solution

4 0

3 years ago

A 426.7 Hz tuning fork is resonating in a closed tube on a warm day when the speed of sound is 346 m/s.

Grace [21]

Answer:0.8 meter

Explanation:

Frequency=426.7hz

Velocity=346m/s

Length =velocity ➗ frequency

Length=346 ➗ 426.7

Length =0.8

8 0

3 years ago