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4 years ago

A 3.8 object is lifted 12 meters. how much work is performed during the lifting?

Physics

2 answers:

Delicious77 [7]4 years ago

7 0

I believe the answer would be 446.9 J.

exis [7]4 years ago

5 0

I can't tell if you're giving me the mass or the weight but the equation for this problem is this:

Force*distance=work

If you already have the weight then just multiply it by the distance but if you have the mass you must multiply it by the gravity also.

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If you had a known sample of a mineral whose density was 7.1 grams/ml and its volume was 15 ml. What is the mass of the mineral.

kow [346]

Answer:

<h3>The answer is 106.5 g</h3>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 15 mL

density = 7.1 g/mL

We have

mass = 7.1 × 15

We have the final answer as

Hope this helps you

6 0

3 years ago

If the outside air temperature increases during a flight at constant power and at a constant indicated altitude, the true airspe

Readme [11.4K]

The true airspeed will increase and true altitude will increase.

<h3>What is true air speed?</h3>

True airspeed is the airspeed of an aircraft relative to undisturbed air.

It's the aircraft speed relative to the airmass in which it's flying.

<h3>How does outside air temperature affect air speed?</h3>

If the outside air temperature increases during a flight at constant power and at a constant indicated altitude, the true airspeed will increase and true altitude will increase.

Thus, the true airspeed will increase and true altitude will increase.

Learn more about true airspeed here: brainly.com/question/13257916

#SPJ1

6 0

2 years ago

que 2. Why do we keep frequency constant instead of keeping vibrating length constam second law of vibrating string?

ella [17]

Answer:

The second law of a vibrating string states that for a transverse vibration in a stretched string, the frequency is directly proportional to the square root of the string's tension, when the vibrating string's mass per unit length and the vibrating length are kept constant

The law can be expressed mathematically as follows;

$f = \dfrac{1}{2\cdot l} \cdot \sqrt{\dfrac{T}{m} }$

The second law of the vibrating string can be verified directly, however, the third law of the vibrating string states that frequency is inversely proportional to the square root of the mass per unit length cannot be directly verified due to the lack of continuous variation in both the frequency, 'f', and the mass, 'm', simultaneously

Therefore, the law is verified indirectly, by rearranging the above equation as follows;

$m = \dfrac{1}{ l^2} \cdot \dfrac{T}{4\cdot f^2} }$

From which it can be shown that the following relation holds with the limits of error in the experiment

m₁·l₁² = m₂·l₂² = m₃·l₃² = m₄·l₄² = m₅·l₅²

Explanation:

8 0

3 years ago

A 70.0-kg person rides in an elevator while standing on a scale. the scale reads 896 n. what is the magnitude and direction acce

Ksju [112]

If the elevator was stationary, the scale would read exactly the weight of the person:
$W=mg=(70 km)(9.8 m/s^2)=686 N$
However, the elevator is moving with an acceleration a, so the scale reads a new value of the weight, which we call W'. Newton's second law becomes
$W' = ma'$
where a' is actually the total acceleration of the person, so it's the sum of the acceleraion of the elevator and of the gravitational acceleration: $a'=a+g$
Taking the direction of g (downward) as the positive direction, we can find the value of a:
$W' = m(a+g)$
$a= \frac{W'}{m}-g= \frac{896 N}{70 kg}-9.8 m/s^2=3 m/s^2$
So, the acceleration of the elevator is $3 m/s^2$ , with same sign of g, so it's directed downward as well.