Answer:
a) r = 4.22 10⁷ m, b) v = 3.07 10³ m / s and c) a = 0.224 m / s²
Explanation:
a) For this exercise we will use Newton's second law where acceleration is centripetal and force is gravitational force
F = m a
a = v² / r
F = G m M / r²
G m M / r² = m v² / r
G M / r = v²
The squared velocity is a scalar and this value is constant, so let's use the uniform motion relationships
v = d / t
As the orbit is circular the distance is the length of the circle in 24 h time
d = 2π r
t = 24 h (3600 s / 1 h) = 86400 s
Let's replace
G M / r = (2π r / t)²
G M = 4 π² r³ / t²
r = ∛(G M t² / (4π²)
r = ∛( 6.67 10⁻¹¹ 5.98 10²⁴ 86400² / (4π²)) = ∛( 75.4 10²¹)
r = 4.22 10⁷ m
b) the speed module is
v = √G M / r
v = √(6.67 10⁻¹¹ 5.98 10²⁴/ 4.22 10⁷
v = 3.07 10³ m / s
c) the acceleration is
a = G M / r²
a = 6.67 10⁻¹¹ 5.98 10²⁴ / (4.22 10⁷)²
a = 0.224 m / s²
Answer:
a small dense nucleus with positive charge and the nucleus is surrounding by orbiting electrons.
Explanation:
An experiment in which alpha particles were used to bombard thin sheets of gold foil led to the conclusion that an atom is composed mostly of a small dense nucleus with positive charge and the nucleus is surrounding by orbiting electrons.
Answer:
B
Explanation:
The impulse experienced by an object is the force•time.
The distance traveled by the egg after 2 seconds is 19.6 m.
The given parameters:
- <em>Height of the window, h = 40 m</em>
The distance traveled by the egg after 2 seconds is calculated as follows;
where;
- <em />
<em> is the initial vertical velocity of the egg = 0</em> - <em>g </em><em>is acceleration due to gravity = 9.8 m/s²</em>
- <em>t </em><em>is the time of motion, = 2 s</em>
Thus, the distance traveled by the egg after 2 seconds is 19.6 m.
Learn more about second equation of motion here: brainly.com/question/7977693
Electric
field strength = Electric force/charge
E = F/q
E = (1.8×10^-1) / (6.4×10^-7)
E = 2.81×10^5 NC^-1
Hope it helped!
