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Vsevolod [243]
3 years ago
5

Which is the numbers 7/8, 0.825, and 0.78 in order from least to greatest?

Mathematics
1 answer:
hichkok12 [17]3 years ago
8 0
0.825, 0.78 and 7/8 because a fraction is less than any other, if I am wrong please correct me. Hope this helps 
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Please help whats the answer !!?
Soloha48 [4]

The correct answer is the one on the top right corner.

3 0
3 years ago
The equation below shows the area of a trapezoid, A, with a height of 9 cm, and one base 35 cm A = 9 over 2(b + 35). Which of th
stepladder [879]
B - the other base;
A = 9/2 ( b + 35 )   / * 2  ( we will multiply both sides of the equation by 2 )
2 A = 9 ( b + 35 )
b + 35 = 2 A / 9 
b + 35 - 35 = 2 A / 9 - 35
b = (2 A / 9 ) - 35
Answer: B ) b = 2 multiplied by A over 9 - 35
8 0
3 years ago
Read 2 more answers
(-3, 117) (0, 45) (3, 27)<br> Quadratic regression
telo118 [61]

Answer:

is it y = -15x + 63

Step-by-step explanation:

8 0
3 years ago
Find the mean of 1.8,1.7,1.3,1.1,1.2,1.6,1.8
Tpy6a [65]

Answer:

1.5

Step-by-step explanation:

To find the mean, we must add all of our terms, and then divide by the number of terms.

1.8+1.7+1.3+1.1+1.2+1.6+1.8

Solve:

1.8+1.7+1.3+1.1+1.2+1.6+1.8=10.5

Since we have seven terms, we must divide our total (10.5), by seven.

10.5 ÷ 7

Solve:

10.5 ÷ 7=1.5

Therefore, the mean is 1.5

8 0
3 years ago
Read 2 more answers
(a) Write down the gradient of the line with equation y = 7 - 4x The line L passes through the points with coordinates (- 3, 1)
lesya [120]

Note: Let us consider, we need to find the gradient of line L.

Given:

The given equation of a line is:

y=7-4x

The line L passes through the points with coordinates (- 3, 1) and (2, - 2).

To find:

The gradient of the given line and the gradient of line L.

Solution:

Slope intercept form of a line is:

y=mx+b                ...(i)

We have,

y=7-4x                   ...(ii)

On comparing (i) and (ii), we get

m=-4

Therefore, the gradient of the given line is -4.

The line L passes through the points with coordinates (- 3, 1) and (2, - 2). So, the gradient of line L is:

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{-2-1}{2-(-3)}

m=\dfrac{-3}{2+3}

m=\dfrac{-3}{5}

Therefore, the gradient of the line L is \dfrac{-3}{5}.

6 0
3 years ago
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