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Hoochie [10]
3 years ago
14

IaI − IbI + IcI , if a=−8; b=−5; c=1pLEEEEEEZE hELP

Mathematics
1 answer:
yawa3891 [41]3 years ago
6 0

Answer:

4

Step-by-step explanation:

to solve | a | - | b | + | c | we need to plug in the given values

a = -8

b = -5

c = 1

the | | bars mean absolute value which is the exact value a number is away from 0 on a number line. an absolute value has to be positive, not a negative, as you cant be negative spaces away from something. plugging in the values into the equation we have:

| -8 | - | -5 | + | 1 |

the absolute value of -8 is 8, as -8 is 8 units away from 0 on a number line

like wise with -5, the absolute value of -5 is 5, as -5 is 5 units away from 0 on a number line

1 is the absolute value of 1 as its 1 unit away from 0 on a number line

the new expression looks like the following:

8 - 5 + 1

now we just add/subtract

8 -5 = 3

3 + 1 = 4

the solution to this expression is 4

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3 years ago
The table below represents an exponential function what is the common ratio
Greeley [361]

Solution:

Given:

A table representing an exponential function.

The x-values represent the terms, while the y-values represent the numbers.

The common ratio is gotten from the numbers (y-values).

The formula for common ratio is given by;

\begin{gathered} r=\frac{present\text{ term}}{preceed\text{ ing term}} \\  \\ \text{Hence,} \\ r=\frac{108}{36}=\frac{36}{12}=\frac{12}{4}=\frac{4}{1.33\ldots}=\frac{1.33\ldots.}{0.44\ldots} \\ r=3 \end{gathered}

Therefore, the common ratio is 3.

3 0
2 years ago
Will give BRAINLIEST to correct answer.<br><br> Given that ℓ1 ∥ ℓ2, find x.
lisov135 [29]

X = 38

2x is equal to the angle next to the x + 66 angle because ℓ1 ∥ ℓ2 is parallel so:

2x + x + 66 = 180 -- combine like terms

3x + 66 = 180 -- subtract 66 from both sides

3x = 114 -- divide by 3 on both side

x = 38

5 0
3 years ago
How much work is done by a cane that lowers 1,000 Newton’s of material a distance of 150 meters
NARA [144]

Answer:

Step-by-step explanation:

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7 0
4 years ago
Many smartphones, especially those of the LTE-enabled persuasion, have earned a bad rap for exceptionally bad battery life. Batt
BartSMP [9]

Answer:

Null hypothesis: the variance in hours of usage for talking is not greater than the the variance in hours of usage for internet.

H_o: \sigma _1 ^2 \leq \sigma _2^2

Alternative hypothesis: the variance  in hours of usage for talking is  greater than the the variance in hours of usage for internet.

H_a : \sigma_1^2 > \sigma_2^2

\mathbf{s_ 1 =16.11}

\mathbf{s_2 = 7.98}

Step-by-step explanation:

Let x_1 and x_2 be the two variables that represents the battery life in hours for talking usage and battery life in hours for internet usage respectively.

The hypothesis can be formulated as:

Null hypothesis: the variance in hours of usage for talking is not greater than the the variance in hours of usage for internet.

H_o: \sigma _1 ^2 \leq \sigma _2^2

Alternative hypothesis: the variance  in hours of usage for talking is  greater than the the variance in hours of usage for internet.

H_a : \sigma_1^2 > \sigma_2^2

The standard deviation for the battery usage for talking is :

\bar x_1 = \dfrac{1}{n_1} \sum x_i  \\ \\ \bar x_1  = \dfrac{1}{12}(35.8 +22.4+...+35.5) \\ \\ \bar x_1 = \dfrac{241.2}{12}  \\ \\ \bar x_1 =20.1

The standard deviation Is:

s_ 1 = \sqrt{\dfrac{1}{n_1-1}\sum (x{_1i}-\bar x_i)^2}

s_ 1 = \sqrt{\dfrac{1}{12-1}\sum (35.8- 20.1)^2+ (35.5-20.1)^2}

s_ 1 = \sqrt{259.568}

\mathbf{s_ 1 =16.11}

The standard deviation for the battery life usage for the internet is :

\bar x_2 = \dfrac{1}{n_2} \sum x_{2i}

\bar x_2 = \dfrac{1}{10} (24.0+12.5+36.4+...+4.7})

\bar x_2 = \dfrac{115}{10}

\bar x_2 = 11.5

Thus; the standard deviation is:

s_2 = \sqrt{\dfrac{1}{n_2-1}(x_{2i}- \bar x_2)^2}

s_2 = \sqrt{\dfrac{1}{10-1}(24-11.5)^2+(4.7-11.5)^2}

s_2 = \sqrt{63.60}

\mathbf{s_2 = 7.98}

4 0
3 years ago
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