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Masteriza [31]
3 years ago
9

a gymnasium is 88 feet long and 76 wide on a blueprint the gymnasium is 5.5 inches long what is the width of the gymnasium on th

e blueprint brainiest pleas3 meed help show work

Mathematics
2 answers:
attashe74 [19]3 years ago
6 0

First we would need to find the portion of the gymnasium to the blueprint to do that please do this:

88/5.5 = 16

The length divided by the blueprint's length

Since we know that the gymnasium is 16 times the blueprint, to find the width divide 16 to 76:

76/16 = 4.75

The width divided by the 16 times

The width of the blueprint is 4.75 inches

snow_tiger [21]3 years ago
3 0

Scale = \frac{88}{5.5} = 16 feet/inch

or 16 feet = 1 inch

Hence, Width = 76 feet x 1 inch/16 feet or \frac{76}{16}= 4.75 inches

Hence, width on the blueprint = 4.75 inches.


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Since ∠K ≅ ∠L, then ΔKLM is an isoceles triangle with base KL

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3x + 23 = 7x - 37

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Use trig to solve for ∠L (which equals ∠K):

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Triangle sum Theorem:

∠K + ∠L + ∠M = 180°    

45.7 + 45.7 + ∠M = 180

       91.4     + ∠M = 180

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