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Masteriza [31]
3 years ago
9

a gymnasium is 88 feet long and 76 wide on a blueprint the gymnasium is 5.5 inches long what is the width of the gymnasium on th

e blueprint brainiest pleas3 meed help show work

Mathematics
2 answers:
attashe74 [19]3 years ago
6 0

First we would need to find the portion of the gymnasium to the blueprint to do that please do this:

88/5.5 = 16

The length divided by the blueprint's length

Since we know that the gymnasium is 16 times the blueprint, to find the width divide 16 to 76:

76/16 = 4.75

The width divided by the 16 times

The width of the blueprint is 4.75 inches

snow_tiger [21]3 years ago
3 0

Scale = \frac{88}{5.5} = 16 feet/inch

or 16 feet = 1 inch

Hence, Width = 76 feet x 1 inch/16 feet or \frac{76}{16}= 4.75 inches

Hence, width on the blueprint = 4.75 inches.


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     Generally the size of the sample sample space is  mathematically represented as

           n  =   \left N } \atop {}} \right.  C_r

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         n  =   \left 19 } \atop {}} \right.  C_8 =  \frac{19 !}{(19 - 8 )! 8!}

                           =     \frac{19 *18 *17 *16 *15 *14 *13 *12 *11! }{11 ! \ 8!}

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    For  b  Where  N  = 25 and  r  =  3

           n  =   \left 25 } \atop {}} \right.  C_3 =  \frac{25 !}{(19 - 3 )! 3!}

                             =     \frac{25 *24 *23 *22 !  }{22 ! \ 3!}

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   For  c  Where  N  = 23 and  r  =  2

            n  =   \left 23 } \atop {}} \right.  C_2 =  \frac{23 !}{(23 - 2 )! 2!}

                              =     \frac{23 *22 *21!  }{21 ! \ 3!}

                              n =   253

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Answer:

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