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GuDViN [60]
3 years ago
8

PLEASE HELP, CHEMISTRY!!! 20 POINTS!!!

Chemistry
2 answers:
krek1111 [17]3 years ago
7 0

Answer: 2HCL (aq) + ZN(s) ZnCl2(s) = H2(g)

Explanation:

mart [117]3 years ago
6 0

the answer is in the picture

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Please help me for 20 points<br> NUMBER 11 ONLY PLEASE <br> LOOK ON PHOTO FOR THE QUESTION, thanks!
Blizzard [7]
Astroid is the answer to the problem
7 0
3 years ago
If U-235 decays into Cs-135 and 4 neutrons, what other nuclide will be produced?
dmitriy555 [2]

If U-235 decays into Cs-135 and 4 neutrons, the other nuclide that will be produced is Rb-96 (option D).

<h3>What is radioactive decay?</h3>

A radioactive decay is the process by which an unstable large nuclei emit subatomic particles and disintegrate into one or more smaller nuclei.

According to this question, a radioactive material Uranium- 235 undergoes radioactive decay into Cs- 135 and 4 neutrons (1/0n).

This means that the mass of the products we have is 135 + 4 = 139.

The mass of the nuclide left must be 235 - 139 = 96, hence, the other nuclide that will be produced is Rb-96.

Learn more about radioactive decay at: brainly.com/question/1770619

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5 0
1 year ago
What volume of a 2.10 M NaCl solution is
cluponka [151]

Answer:

146.3g NaCl (mol NaCl/58.44g NaCl) = 2.50 mol NaCl

1.5M NaCl = 1.5 mol NaCl / 1 L = 2.5 mol NaCl / x L, solve for x

x L = 2.5 mol NaCl / 1.5 mol NaCl = 1.66 L

It gives the answer and all the working.

To put it another way:

Dividing the amount required by the molar mass

we quickly see that 2.5 moles are required.

One litre of 1.5 molar solution gives 1.5 moles

we need a further mole, which is 2/3 of 1.5 so 2/3 of a litre.

3 0
3 years ago
If the fugacity of a pure component at the conditions of an ideal solution is 40 bar and its mole fraction is 0.4, what is its f
yaroslaw [1]

Answer : The fugacity in the solution is, 16 bar.

Explanation : Given,

Fugacity of a pure component = 40 bar

Mole fraction of component  = 0.4

Lewis-Randall rule : It states that in an ideal solution, the fugacity of a component is directly proportional to the mole fraction of the component in the solution.

Now we have to calculate the fugacity in the solution.

Formula used :

f_i=X_i\times f_i^o

where,

f_i = fugacity in the solution

f_i^o = fugacity of a pure component

X_1 = mole fraction of component

Now put all the give values in the above formula, we get:

f_i=0.4\times 40\text{ bar}

f_i=16\text{ bar}

Therefore, the fugacity in the solution is, 16 bar.

4 0
3 years ago
What are three of Leonardo divinci's contributions to science?
Zielflug [23.3K]
<span> hydraulic pumps, flying machines, and war machines.</span>
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