The net ionic equations in
the creation of solid Hg2Cl2 and aqueous Sodium Nitrate (NaNO3) would be:
Hg2(NO3)2 + 2 NaCl
--------> Hg2Cl2 + 2 NaNO3 <span>
Hg2+2 + 2NO3-1 + 2Na+ Cl- ----> Hg2Cl2 + 2Na+ + 2NO3-1
<span>Hg2+2 + 2Cl-1 ------------> Hg2Cl2</span></span>
Answer:
0.028kg
Explanation:
We were given 2.6 × 1023 molecules of SO 2 That means that
N = 2.6 × 1023 molecules
Use
n (number of moles) = N
NA (Avogadro's constant)
to get
n =2.6×1023 molecules
6.02 ×1023 molecules/mol = 0.432 moles
Now use
m = n × M (molar mass)
to get
m = 0.432 mol × 64.066 g/mol = 27.677 g
So
m (in kilograms) = 27.677 g
103 g/kg = 0.028 kg
Explanation:
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