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Anarel [89]
2 years ago
10

The following is a chemical reaction for _______ with ozone.

Chemistry
2 answers:
ExtremeBDS [4]2 years ago
6 0

B. Halons...................

Naily [24]2 years ago
3 0
<span>unreactive gaseous compounds of carbon with halogens, that is used in fire extinguishers, and is very harmful for ozone layer are called as halons .
So according to above explanantion,
</span><span>b. halons, is the correct answer.</span>
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Why does a reaction slow down with time?
MrMuchimi

Answer:

first mark me  Brainliest

Explanation:

Reaction rate, in chemistry, the speed at which a chemical reaction proceeds. It is often expressed in terms of either the concentration (amount per unit volume) of a product that is formed in a unit of time or the concentration of a reactant that is consumed in a unit of time. Alternatively, it may be defined in terms of the amounts of the reactants consumed or products formed in a unit of time. For example, suppose that the balanced chemical equation for a reaction is of the form

A + 3B → 2Z.

4 0
2 years ago
Read 2 more answers
What group will group 16 most likely bond with?
ikadub [295]
They will most likey group with the second group. Since they have 6 electrons and want to have a full outer shell so therefore would group with the second group.
7 0
2 years ago
How many cm3 are contained in 3.83 x 107 mm3?
gulaghasi [49]

Answer:

3.38 x 10⁴cm³

Explanation:

Given that:

      Volume of the substance  = 3.83 x 10⁷mm³

The problem entails use to convert from mm³ to cm³;

                    1000mm³   = 1cm³

So;

          3.83 x 10⁷mm³ will produce \frac{ 3.83 x 10^{7} }{1000}    = 3.38 x 10⁴cm³

5 0
3 years ago
Calculate the wavelength, in nanometers, of the light emitted by a hydrogen atom when its electron fallsfrom the n = 7 to the n
Helga [31]

Answer:

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

Explanation:

We recall that Eₙ=\frac{-2.18*10^{-18} J}{n^{2} }

since there was transition from n7 to n=4 we will first calculate the change in the energy i.e ΔE

ΔE=E₄-E₇

ΔE=-2.18*10^{-18} J(\frac{1}{4^{2} } -\frac{1}{7^{2} } )

ΔE=-9.1760*10^-20 J

Now:

|ΔE|=Energy of photon=h*v=h*c/λ

λ=h*c/|ΔE|

λ=\frac{6.63*10^{-34}J.s*3.00*10^{8}m/s  }{9.1760*10^{-20} J }

λ=2.1676*10^-6 m

λ=2167.6*10^-9 m

λ=2167.6 nm

The wavelength of light emitted is 2167.6 nm.

5 0
3 years ago
Lithium (Li) and oxygen (O) are both in period 2. They both have _____.
AlladinOne [14]

They both have two electron shells

<h3>Further explanation</h3>

The period 2 element lies in the second row of the periodic system.

Consists of the elements: lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine, and neon

  • Lithium (Li)

atomic number : 3

electron configuration : [He] 2s¹

atomic number = number of proton=number of electron(in neutral atom)

So Li have 3 protons and 3 electrons

Because it fills the 2s orbital it has 2 shells

  • Oxygen (O)

atomic number : 8

electron configuration :  [He] 2s²2p⁴

So O have 8 protons and 8 electrons

Because it fills the 2s and 2p orbital it has 2 shells

So Lithium (Li) and Oxygen (O) are both have two electron shells

6 0
2 years ago
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