Answer:
Present Time
Let X= Eric's age (4/5)X= Seth's age
Question: What are their ages now?________________________________________________________________________
Past (21 years ago)
X-21 =Eric's age (4/5)X-21=Seth's age
2*[4/5(X-21]=Eric's age
Therefore, X-21= 2*[4/5(X)-21]=Eric's age Substitution
_______________________________________________________________________
X-21= 8/5 X - 42 Solve for "X" by adding 42 to both sides.
X-21+42=(8/5) X
X+21 = (8/5)X Subtract "X" from both sides.
21=(3/5)X Multiply both sides of equation by reciprocal of (3/5), which is 5/3
21*(5/3)= X Finish the problem to find value of "X," which is Eric's age.
Then find 4/5 (X)= Seth's age
The answer is true hop that helped
If you are asking if 8.25 is greater than than 8.250, the answer would be no because any zero that is extended from the original number would still be the same.
ex: 6.2 and 6.200000000
(The zeros could go on forever and it would still be the same number)
~Hope I Helped
Answer:
width= 6
Step-by-step explanation:
equation: 50=2(2w-5)+ 2w w= width
50=6w-10
60=6w
w=6
