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3 years ago

Name the following hydrocarbons

Chemistry

1 answer:

jekas [21]3 years ago

4 0

Answer:

1) Pentane 2) 2-Pentene

Explanation:

Both molecules have five carbons so you will add thhe prefix "pent-" and the first molecule only has single bonds so it will end in "-ane" because is it an Alkane. The second hydrocarbon has a double bond; therefore, it's a Alkene resulting in the ending of "-ene". BUT the double bond is located on the second carbon; therefore you must add "2-" before the name.

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Calculate the percent yield of a reaction where a student collected 16.8 grams of product and was expecting to collect 49.7 gram

masya89 [10]

Answer:

$\boxed{\text{33.8 \%}}$

Explanation:

$\text{\% yield} = \dfrac{\text{actual yield}}{\text {theoretical yield}} \times\text{100 \%}$

Data:

Actual yield = 16.8 g

Theoretical yield = 49.7 g

Calculation:

$\text{\% yield} = \dfrac{\text{16.8 g}}{\text {49.7 g}} \times\text{100 \%} = \boxed{\textbf{33.8 \%}}$

8 0

3 years ago

Help please with question number 16)

Zanzabum

Answer:

Mg²⁵ = 10.00%

Mg²⁶ = 45.04%

Mg²⁴ = 44.96%

Explanation:

Given data:

Atomic mass of Mg²⁶ = 25.983

Atomic mass of Mg²⁵ = 24.986

Atomic mass of Mg²⁴ = 23.985

Abundance of Mg²⁵ = 10.00%

Abundance of Mg²⁶ = ?

Abundance of Mg²⁴ = ?

Solution:

Average atomic weight of Mg = 25.983 + 24.986+ 23.985 / 3

Average atomic weight of Mg = 74.954/3

Average atomic weight of Mg = 24.985 amu

Abundance of

Mg²⁵ = 10.00

Mg²⁶ = x

Mg²⁴ = 100- 10 - x = 90 -x

Formula:

Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass) / 100

24.985 = (0.1×24.986)+(90-x×23.985) + ( x ×25.983 ) /100

24.985 = 249.86 + 2158.65 - 23.985x + 25.983x / 100

24.985 = 2408.51 + 1.998 x / 100

2498.5 = 2408.51 + 1.998 x

1.998 x = 2498.5 - 2408.51

1.998 x = 89.99

x = 89.99 /1.998

x = 45.04

Now we put the value of x:

Mg²⁵ = 10.00

Mg²⁶ = x (45.04)

Mg²⁴ = 90 -x (90 - 45.04 = 44.96)

5 0

3 years ago

Nitric acid is a key industrial chemical, largely used to make fertilizers and explosives. The first step in its synthesis is th

Hunter-Best [27]

Answer:

The answer is 0.36 kg/s NO

Explanation:

the chemical reaction of NH3 to NO is as follows:

4NH3(g) + 5O2(g) ⟶4 NO(g) +6 H2O(l)

We have the following data:

O2 Volume rate = 645 L/s

P = 0.88 atm

T = 195°C + 273 = 468 K

NO molecular weight = 30.01 g/mol

we calculate the moles found in 645 L of O2:

P*V = n*R*T

n = P*V/R*T

n= (0.88 atm * 645L/s)/((0.08205 L*atm/K*mol) * 468 K) = 14.78 moles of O2

With the reaction we can calculate the number of moles of NO and with its molecular weight we will have the rate of NO:

14.78 moles/s O2 * 4 molesNO/5 molesO2 * 30.01 g NO/1 molNO x 1 kgNO/1000 gNO = 0.36 kg/s NO

8 0

4 years ago

Identify the cfc with the shortest atmospheric lifetime

goldenfox [79]

CFC-11 is typically the CFC with the shortest atmospheric lifetime.

5 0

3 years ago

Oxana [17]

Answer:

1422mg of acetaminophen

Explanation:

The maximum dose of acetaminophen is 15.0 mg of acetaminophen per kg of person.

To know the maximum single dosage of the person we need to convert the 209lb to kg (Using 1kg = 2.2046lb):

209lb * (1kg / 2.2046lb) = 94.8

The person weighs 94.8kg and the maximum single dosage for the person is:

94.8kg * (15.0mg acetaminophen / kg) =

1422mg of acetaminophen

4 0

3 years ago