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3 years ago

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When Earth is between the Moon and the Sun, the fully lit face of the Moon is seen from Earth. This phase of the Moon is called

a ________ moon.
A) crescent
B) full
C) gibbous
D) new

1 answer:

alexandr1967 [171]3 years ago

6 0

B) full
When the moon is fully lit up, you can see all of it, therefore it is a full moon.

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The thin layer that separates a cells contents from the outside environment is the A.cell membrane b.nucleus c.cytoplasm D.endop

Vikentia [17]

The answer is A) Cell Membrane

8 0

3 years ago

What creates an electric current in a battery?

kramer

Answer:

There's a separate chemical reaction happening at the positive electrode, where incoming electrons recombine with ions taken out of the electrolyte, so completing the circuit. The electrons and ions flow because of the chemical reactions happening inside the battery—usually two of them going on simultaneously.

Explanation:

option (B) is right

7 0

3 years ago

2.3 Zinc has five naturally occurring isotopes: 48.63% of 64 Zn with an atomic weight of 63.929 amu; 27.90% of 66Zn with an atom

lakkis [162]

<u>Answer:</u> The average atomic mass of element Zinc is 65.40 amu.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

<u>For $_{30}^{64}\textrm{Zn}$ isotope:</u>

Mass of $_{30}^{64}\textrm{Zn}$ isotope = 63.929 amu

Percentage abundance of $_{30}^{64}\textrm{Zn}$ isotope = 48.63 %

Fractional abundance of $_{30}^{64}\textrm{Zn}$ isotope = 0.4863

<u>For $_{30}^{66}\textrm{Zn}$ isotope:</u>

Mass of $_{30}^{66}\textrm{Zn}$ isotope = 65.926 amu

Percentage abundance of $_{30}^{66}\textrm{Zn}$ isotope = 27.90 %

Fractional abundance of $_{30}^{66}\textrm{Zn}$ isotope = 0.2790

<u>For $_{30}^{67}\textrm{Zn}$ isotope:</u>

Mass of $_{30}^{67}\textrm{Zn}$ isotope = 66.927 amu

Percentage abundance of $_{30}^{67}\textrm{Zn}$ isotope = 4.10 %

Fractional abundance of $_{30}^{67}\textrm{Zn}$ isotope = 0.0410

<u>For $_{30}^{68}\textrm{Zn}$ isotope:</u>

Mass of $_{30}^{68}\textrm{Zn}$ isotope = 67.925 amu

Percentage abundance of $_{30}^{68}\textrm{Zn}$ isotope = 18.75 %

Fractional abundance of $_{30}^{68}\textrm{Zn}$ isotope = 0.1875

<u>For $_{30}^{70}\textrm{Zn}$ isotope:</u>

Mass of $_{30}^{70}\textrm{Zn}$ isotope = 69.925 amu

Percentage abundance of $_{30}^{70}\textrm{Zn}$ isotope = 0.62 %

Fractional abundance of $_{30}^{70}\textrm{Zn}$ isotope = 0.0062

Putting values in equation 1, we get:

$\text{Average atomic mass of Zinc}=[(63.929\times 0.4863)+(65.926\times 0.2790)+(66.927\times 0.0410)+(67.925\times 0.1875)+(69.925\times 0.0062)]$

$\text{Average atomic mass of Zinc}=65.40amu$

Hence, the average atomic mass of element Zinc is 65.40 amu.

7 0

3 years ago

Describe how physical and chemical change may have affected by temperature

stepladder [879]

The heat changes the physical structure into a chemical structure because some of the cells in the physical structure are removed to make that physical structure a chemical structure

7 0

3 years ago

Read 2 more answers

Tritium 3 1H decays to 3 2He by beta emission. Find the energy released in the process. Answer in units of keV.

-Dominant- [34]

Answer:

The energy released in the decay process = 18.63 keV

Explanation:

To solve this question, we have to calculate the binding energy of each isotope and then take the difference.

The mass of Tritium = 3.016049 amu.

So,the binding energy of Tritium = 3.016049 *931.494 MeV

= 2809.43155 MeV.

The mass of Helium 3 = 3.016029 amu.

So, the binding energy of Helium 3 = 3.016029 * 931.494 MeV

= 2809.41292 MeV.

The difference between the binding energy of Tritium and the binding energy of Helium is: 32809.43155 - 2809.412 = 0.01863 MeV

1 MeV = 1000keV.

Thus, 0.01863 MeV = 0.01863*1000keV = 18.63 keV.

So, the energy released in the decay process = 18.63 keV.

7 0

3 years ago