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3 years ago

11

When Earth is between the Moon and the Sun, the fully lit face of the Moon is seen from Earth. This phase of the Moon is called

a ________ moon.
A) crescent
B) full
C) gibbous
D) new

1 answer:

alexandr1967 [171]3 years ago

6 0

B) full
When the moon is fully lit up, you can see all of it, therefore it is a full moon.

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HELP PLEASE THIS IS CONFUSING

Rasek [7]

Number of moles = 8.3 x 10⁻¹³

<h3>Further explanation </h3>

The mole is the number of particles(molecules, atoms, ions) contained in a substance

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

5 x 10¹¹ atoms of Silver :

$\tt mol=\dfrac{5\times 10^{11}}{6.02\times 10^{23}}=8.3\times 10^{-13}$

5 0

3 years ago

40. What is the mass of 3 moles of H 2 O

Leya [2.2K]

Answer:

54g

Explanation:

Given parameters:

Number of moles of H₂O = 3 moles

Unknown:

mass of water = ?

Solution:

To solve this problem, we use the expression below:

mass = number of moles x molar mass

Molar mass of H₂O = 2(1) + 16 = 18g/mol

Mass of water = 3 x 18 = 54g

3 0

3 years ago

Various members of a class of compounds, alkenes, react with hydrogen to produce a corresponding alkane. Termed hydrogenation, t

Vitek1552 [10]

<u>Answer:</u> The mass of decane produced is $1.743\times 10^2g$

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

Mass of hydrogen gas = 2.45 g

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1:, we get:

$\text{Moles of }H_2=\frac{2.45g}{2g/mol}=1.225mol$

The chemical equation for the hydrogenation of decene follows:

$C_{10}H_{20}(l)+H_2(g)\rightarrow C_{10}H_{22}(s)$

As, decene is present in excess. So, it is considered as an excess reagent.

Thus, hydrogen gas is a limiting reagent because it limits the formation of products.

By Stoichiometry of the reaction:

1 mole of hydrogen gas produces 1 mole of decane.

So, 1.225 moles of hydrogen gas will produce = $\frac{1}{1}\times 1.225=1.225mol$ of decane

Now, calculating the mass of decane by using equation 1, we get:

Moles of decane = 1.225 mol

Molar mass of decane = 142.30 g/mol

Putting values in equation 1, we get:

$1.225mol=\frac{\text{Mass of decane}}{142.30g/mol}\\\\\text{Mass of carbon dioxide}=(1.225mol\times 142.30g/mol)=174.3g=1.743\times 10^2g$

Hence, the mass of decane produced is $1.743\times 10^2g$

5 0

3 years ago

Which of the following groups of materials would

Nikitich [7]

The wrong answers for sure are B and D, I assume the answer is C

4 0

3 years ago

Read 2 more answers

Water and ammonium nitrate (NH4NO3) react in an endothermic reaction in a beaker. What would you expect to observe during this r

maksim [4K]

Answer:

The beaker will get colder

Explanation:

3 0

3 years ago