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3 years ago

Expression for the calculation the sum of the product of 4 and 3 and 1 and 1

Mathematics

1 answer:

VLD [36.1K]3 years ago

8 0

Answer:

(4 × 3) + (1 × 1)

Step-by-step explanation:

Sum means adding, so you are adding the product of 4 and 3 to the product of 1 and 1.

Product means multiplying, so you are multiplying 4 and 3 together, and since you just want an expression, this is expressed as 4 × 3.

You are also multiplying 1 and 1 together, so that can be expressed by 1 × 1.

Since you are adding these together, you just put a plus sign in between the two terms. That gives you (4 × 3) + (1 × 1).

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Suppose you roll a standard number cube and spin a spinner with four equal-sized sections labeled 1, 2, 3, 4. What is the probab

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Answer:

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Step-by-step explanation:

If we have two events, A and B, and they are independent, we have that:

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In this question:

Event A: Rolling a prime number.

Event B: Spinning a prime number.

Both the cube and the spinner have four values, ranging from one to four.

2 and 3 are prime values, that is, 2 of those values. Then

$P(A) = P(B) = \frac{2}{4} = \frac{1}{2}$

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The cube and the spinner are independent of each other. So

$P(A \cap B) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} = 0.25$

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3 years ago

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Answer:

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Step-by-step explanation:

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Deﬁne the function add_mn that takes two integers m, n as arguments and returns m + 10 * n. For instance, add_mn 3 5 = 3 + 10*5

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Answer:

// C++ Program to arithmetic operationf on 2 Numbers using Recursion

// Comments are used for explanatory purpose

#include <bits/stdc++.h>

using namespace std;

// add10 recursive function to perform arithmetic operations

int add10(int m, int n)

{

return (m + product(n, 10)); //Result of m + n * 10

return 0;

}

// Main Methods Starts here

int main()

{

int m, n; // 2 Variables m and n declared as integer

cin>>m; // accept input for m

cin>>n; // accept input for n

cout << "Result : "<<add10(m,n); // Print results which is calculated by m + 10 * n

return 0;

}

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3 years ago