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stiv31 [10]
4 years ago
14

Suppose that, from measurements in a microscope, you determine that a certain bacterium covers an area of 1.50μm2. Convert this

to square meters.
Express your answer in square meters.
Chemistry
2 answers:
Lelu [443]4 years ago
6 0
Create your conversion factors.

You know that 1 micrometer = 1/1000000 m

Then,

[1 micrometer]^2 =[1/1000000 m]^2 =>

=> 1 = [1000000]^2 micrometer^2 / m^2

Now multiply the given area times your conversion factor:

1.50 (micrometer)^2 * [1/1000000]^2  micrometer^2 / m^2 = 1.50*10^(-12) m^2

Answer: 1.50*10^(-12) m^2

Step2247 [10]4 years ago
6 0

The area covered by a certain bacterium is equivalent to 1.5 x 10^-12 square meters.

<h3>FURTHER EXPLANATION</h3>

This is an example of conversion within the metric system.

To begin, it is important to remember some basic conversion:

  • 1 meter (m) = 1,000,000 micrometers (μm)
  • 1 meter (m) = 1000 millimeters (mm)
  • 1 meter (m) = 100 centimeters (cm)
  • 1 kilometer (km)= 1000 meter (m)

The relationships above may be used to convert from one unit to another.

In solving the problem it is first important to get the conversion from μm2 to m2 since it is not directly given among the basic conversions.

First, start with what is known:

1 \ m \ = 1,000,000 \mu m

Square both sides:

(1 \ m)^2 \ = (1,000,000 \ \mu m)^2\\1 \ m^2 = 10^{12} \ \mu m

Now that the conversion from μm2 to m2 is known, proceed with the given and convert as show below:

area \ = (1.50 \ \mu m^2 )(\frac{1 \ m^2}{10^{12} \ \mu m^2})\\\boxed {area \ = 1.50 \ x \ 10^{-12} \ m^2}

Since a meter is much larger than the micrometer, a small value in micrometers will be equivalent to an even smaller numerical value in meters. The value 1.50 x 10^-12 m2 makes sense as this is a very very small number.

<h3>LEARN MORE </h3>
  • Metric System brainly.com/question/3623718
  • Dimensional Analysis brainly.com/question/1557970

Keywords: metric conversion

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Answer:

11.4

Explanation:

Step 1: Given data

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NH₃(aq) + H₂O(l) ⇄ NH₄⁺(aq) + OH⁻(aq)

Step 3: Calculate the concentration of OH⁻

We will use the following expression.

[OH^{-} ]=\sqrt{Kb \times Cb } = \sqrt{1.8  \times 10^{-5} \times 0.300 } = 2.3 \times 10^{-3} M

Step 4: Calculate the pOH

We will use the following expression.

pOH =-log[OH^{-} ]= -log(2.3 \times 10^{-3} M) = 2.6

Step 5: Calculate the pH

We will use the following expression.

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Select the correct answer from each drop-down menu.
earnstyle [38]

Answer:

The granite block transferred <u>4080 joules</u> of energy, and the mass of the water is <u>35.84 grams</u>.

Explanation:

The equation needed to answer both parts of the question is:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

<u>Part #1:</u>

First, you need to find the energy transferred from granite block using the previous equation. You have been given the mass, specific heat, and change in temperature.

Q = ? J                            c = 0.795 J/g°C

m = 126.1 g                     ΔT = 92.6 °C - 51.9 °C = 40.7 °C

Q = mcΔT

Q = (126.1 g)(0.795 J/g°C)(40.7 )

Q = 4080

<u>Part #2:</u>

Secondly, using the energy calculated in Part #1, you need to calculate the mass of the water. You have calculated the energy transferred, and have been given the specific heat and change in temperature.

Q = 4080 J                     c = 4.186 J/g°C

m = ? g                            ΔT = 51.9 °C - 24.7 °C = 27.2 °C

Q = mcΔT

4080 J = m(4.186 J/g°C)(27.2 °C)

4080 J = m(113.8592)

35.84 = m

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2 years ago
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