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2 years ago

Select the correct answer from each drop-down menu.

Chemistry

1 answer:

earnstyle [38]2 years ago

4 0

Answer:

The granite block transferred 4080 joules of energy, and the mass of the water is 35.84 grams.

Explanation:

The equation needed to answer both parts of the question is:

Q = mcΔT

In this equation,

-----> Q = energy/heat (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature (°C)

Part #1:

First, you need to find the energy transferred from granite block using the previous equation. You have been given the mass, specific heat, and change in temperature.

Q = ? J c = 0.795 J/g°C

m = 126.1 g ΔT = 92.6 °C - 51.9 °C = 40.7 °C

Q = mcΔT

Q = (126.1 g)(0.795 J/g°C)(40.7 )

Q = 4080

Part #2:

Secondly, using the energy calculated in Part #1, you need to calculate the mass of the water. You have calculated the energy transferred, and have been given the specific heat and change in temperature.

Q = 4080 J c = 4.186 J/g°C

m = ? g ΔT = 51.9 °C - 24.7 °C = 27.2 °C

Q = mcΔT

4080 J = m(4.186 J/g°C)(27.2 °C)

4080 J = m(113.8592)

35.84 = m

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3 years ago

Read 2 more answers

How much energy is required to heat 36.0 g H2O from a liquid at 65°C to a gas at 115°C? The following physical data may be usefu

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Answer:

energy required=qnet=87.75kJ

Explanation:

we will do it in three seperate step and then add up those value.

first step is to heat the sample of water upto 100C i.e upto boiling pont. because just after this sample of water started vaporization.

q 1= m c (T2-T1)

q1 = 36.0 g (4.18 J/gC) (100 - 65 C)

q1 = 5267 J =5.267kJ

next is to vaporize the sample at 100C

q2 = 36.0 g / 18.0 g/mol X 40.7 kJ/mol

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q3 = m c (T2-T1)

q 3= 36.0 g (2.01 J/gC)(115-100C)

q3 = 1085 J =1.085kJ

qnet=q1 +q2 +q3

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3 years ago

When 500.0 g of water is decomposed by electrolysis and the yield of hydrogen is only 75.3%, how much hydrogen chloride can be m

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The amount of hydrogen chloride that can be made is 1064 g

Why?

The two reactions are:

2H₂O → 2H₂ + O₂ 75.3 % yield

H₂ + Cl₂ → 2HCl 69.8% yield

We have to apply a big conversion factor to go from grams of water (The limiting reactant), to grams of HCl, the final product. We have to be very careful with the coefficients and percentage yields!

$500.0gH_2O*\frac{1moleH_2O}{18.01 gH_2O}*\frac{2 moles H_2}{2 moles H_2O}*\frac{2.015g H_2}{1 mole H_2}*\frac{75.3 actual g}{100 theoretical g}=42.12 g H_2$

$42.12H_2*\frac{1 mole H_2}{2.015gH_2}*\frac{2 moles HCl}{1 mole H_2}*\frac{36.46g}{1 mole HCl}*\frac{69.8 actualg}{100 theoreticalg} =1064gHCl$

Have a nice day!

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4 years ago

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3 years ago

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3 years ago