Answer:
C. 30 kJ
Explanation:
Hello there!
In this case, in agreement to the thermodynamic definition of the Gibbs free energy, in terms of enthalpy of entropy:

It is possible to calculate the required G by plugging in the given entropy and enthalpy as shown below:

Therefore, the answer is C. 30 kJ
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Answer:
Explanation:
Enertia is an integral part of Newton's first law of motion.
It is the tendency of an object to <u>stay at rest</u> or <u>to continue moving</u> until and unless <u>any external unbalanced force</u>, (like, applied force or force of tension or frictional force ) is applied to either move it from rest or change its speed(in other words, accelerate it!!).
Example below, is of ball at rest (fig1) and if this ball is moving straight on a frictionless surface(like ice) it will keep moving!! until, we push it or pull it.
Answer:
Weak bonds require less energy to form than strong bonds
Explanation:
According to Coulomb's law, the force between two species is inversely proportional to the distance between them. That said, the bigger the atoms are, the greater the bond length should be to form a molecule.
As a result, for a greater bond length, the attraction force is lower than for a shorter bond length. This implies that large atoms would form weak bonds and small atoms would form strong bonds.
Bond energy is defined as the amount of energy required to break the bond. If a bond is weak, it would require a low amount of energy to break it. This is also true for energy of formation, as it's the same process taking place in the opposite direction.
Answer:
Volume = 30cm³
Explanation:
A block is a geometrical figure and its volume, -look at the figure-, follows the equation:
Volume = Width*Length*Height
As the measurements of the block are 5.00cm, 3.00cm and 2.00cm, the volume is:
Volume = 5.00cm*2.00cm*3.00cm
<h3>Volume = 30cm³</h3>
The correct option is C. The amount of MgCl2. we know this because <span>no matter how much you increase KOH, if you dont increase Mgcl2, the amount of Mg(OH)2 remains the same. Hope this works for you</span>