All categories

3 years ago

Which diagram shows a pair of electrons that have opposite spins? OT 11 11 个个

Chemistry

2 answers:

yanalaym [24]3 years ago

6 1

Answer:

???

Explanation:

Not sure what they mean

Nikolay [14]3 years ago

4 1

Answer:

hi myself from india

you from ??

You might be interested in

Which of the following correctly represents the radioactive decay of cesium-137?<br><br>

pishuonlain [190]

What are the answers ??

5 0

3 years ago

A science student observes that a dissolvable antacid tablet acts faster in relieving stomach pain when taken with warm water th

LekaFEV [45]

Answer:the medication would not last as long

Explanation:

Because of the desolving of the tablet so quickly it would

4 0

3 years ago

Read 2 more answers

PLS HELP ME I HAVE TILL 12

MariettaO [177]

Answer:

alright bud lets see hmm.... the answer is a. 90.5kpa

Explanation:

92.3 kPa - 1.82 kPa = 90.5 kPa

keep up your hope also corrected me if a am wrong in anyway! :)

3 0

3 years ago

PLEASE HELP CHEMITRY!

Delicious77 [7]

Answer:

Explanation:

5 0

2 years ago

How long does it take to electroplate 0.5 mm of gold on an object with a surface area of 31 cm^^ from an Au3+(aq) solution with

konstantin123 [22]

Answer:

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

Explanation:

Mass of gold = m

Volume of gold = v

Surface area on which gold is plated = $a=31 cm^2$

Thickness of the gold plating = h = 0.5 mm = 0.05 cm

1 mm = 0.1 cm

$V=a\times h=31 cm^2\times 0.05 cm=1.55 cm^3$

Density of the gold = $d=19.3 g/cm^3$

$m=d\times v=19.3 g/cm^3\times 1.55 cm^3=29.915g$

Moles of gold = $\frac{29.915 g}{197 g/mol}=0.152 mol$

$Au^{3+}+3e^-\rightarrow Au$

According to reaction, 1 mole of gold required 3 moles of electrons,then 0.152 moles of gold will require :

$\frac{3}{1}\times 0.152 mol=0.456 mol$ of electrons

Number of electrons = N = $0.456\times \times 6.022\times 10^{23}$

Charge on single electron = $q=1.6\times 10^{-19} C$

Total charge required = Q

$Q=N\times q$

Amount of current passes = I = 8 Ampere

Duration of time = T

$I=\frac{Q}{T}$

$T=\frac{N\times q}{I}$

$=\frac{0.456\times \times 6.022\times 10^{23}\times 1.6\times 10^{-19} C}{8 A}=5492 s$

It will take 5492 seconds to electroplate 0.5 mm of gold on an object .

7 0

3 years ago