Find the surface area of a triangular prism that has the following dimensions. Use the formula SA = 2B + Ph.

2 answers:

OverLord2011 [107]4 years ago

7 0

Answer: The surface area of the triangular prism is 448 square millimeters.

To find the surface area, we just need to input our values into the formula that is given.

SA = 2B + Ph
SA = 2(84) + 56(5)
SA = 168 + 280
SA = 448

The final surface area is 448 mm^2.

lisabon 2012 [21]4 years ago

6 0

We know that
the surface area of a triangular prism is
SA = 2B + Ph--------> 2*84+56*5-------------> SA=448 mm²

the answer is 448 mm²

You might be interested in

Need answer asap I’m timed!!!

Ugo [173]

Should be option 1. i cant really gv an explanation tho sry :/

3 0

4 years ago

You deposit $1,000 for years at an interest rate of 2.0%.If the interest is compounded guardedly.How much money would you have a

Stells [14]

Principle(P)=$1000
Rate (r)=2%=0.02
Time=t=4 years
n=no of times the interest is compounded per year=4
Amount (A)=?
Then,
A=P{(1+r/n)}^(n×t)
=1000{1+0.02/4}^(4×4)
=1000×(1.005^16)
=1000 × 1.08307115
=1083.07115
=1083.07 (approx)

Thus at the end of 4 years the amount of money will be Rs 1083.070 approximately.

Hope this helps....

8 0

3 years ago

PLEASE HELP IM TERRIBLE AT MATH!!!! WILL GIVE BRAINLIEST!!!

erastova [34]

Answer:

It is C

Step-by-step explanation:

(3x-2)(x+2)

3x(x)+3x(2)-2(x)-2(2)

3x^2+6x-2x-4

3x^2+4x-4 <----------

(Im bad at explaining but that is right trust me :P)

3 0

3 years ago

The gypsy moth is a serious threat to oak and aspen trees. A state agriculture department places traps throughout the state to d

k0ka [10]

Part A:

From the central limit theorem, since the number of samples is large enough (up to 30), the mean of the the mean of the average number of moths in 30 traps is 0.6.

Part B:

The standard deviation is given by the population deviation divided by the square root of the sample size.

$standard \ deviation= \frac{\sigma}{\sqrt{n}} = \frac{0.4}{\sqrt{30}} = \frac{0.4}{5.477} =0.073$

Part C:

The probability that an approximately normally distributed data with a mean, μ, and the standard deviation, σ, with a sample size of n is greater than a number, x, given by

$P(X\ \textgreater \ x)=1-P(X\ \textless \ x) \\ \\ =1-P\left(z\ \textless \ \frac{x-\mu}{\sigma/\sqrt{n}} \right)$

Thus, given that the mean is 0.6 and the standard deviation is 0.4, the probability that the average number of moths in 30 traps is greater than 0.7 given by:

$P(X\ \textgreater \ 0.7)=1-P(X\ \textless \ 0.7) \\ \\ =1-P\left(z\ \textless \ \frac{0.7-0.6}{0.073} \right)=1-P(z\ \textless \ 1.369) \\ \\ =1-0.91455=\bold{0.0855}$

7 0

4 years ago

What is the slope of the line? (Enter the number only.) Slope=

BigorU [14]

I think it’s 25 and two half’s

8 0

3 years ago

Read 2 more answers