Question

What is the density of a mineral with a mass of 41.2 g and a volume of 8.2 cm3? 49.4 g/cm3 5.02 g/cm3 0.19 g/cm3 337.8 g/cm3

Answer 1

I think the correct answer would be 5.02g cm3 

Answer 2

Answer:

Density of the mineral is equal to $5.02 \frac{g}{cm^{3} }$

Explanation:

The density of a substance is equal to mass of the substance divided by its volume.

Thus, the formula of density (d) is as follows

$d = \frac{M}{V}$

Where, M represent the mass of a substance

and V represents the volume of the same substance

Substituting the given values in above equation, we get -

$d = \frac{41.2}{8.2} \frac{g}{cm^{3} } \\d = 5.02 \frac{g}{cm^{3} }$

Hence, option B is correct