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2 years ago

12

S.V.P URGENT! Mégane à payé 345$ pour un iPod avec des taxes de 14.975% et un rabais de 5%. Quel est le prix régulier ( problème

de secondaire 2)

1 answer:

weqwewe [10]2 years ago

3 0

Answer:

6383.08

Step-by-step explanation:

J'ai dû utiliser google translate, mais j'espère que cela vous aidera.

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Mohit pays rupees 9000 as an amount on the sum of rupees 7000 that he had borrowed for 2 years.

Sphinxa [80]

Answer:

The required rate of interest = 14.285%

Step-by-step explanation:

Here, The principal amount = 7,000

The final paid amount = 9,000

Time = 2 years

Let us assume the rate of interest = R

Now, Simple Interest = Amount - Principal

= 9,000 - 7,000 = 2,000

So, the SI on the given principal for 2 years = 2,000

$\textrm{SIMPLE INTEREST } = \frac{P \times R \times T}{100}\\\implies 2000 = \frac{7,000 \times R \times 2}{100}\\\implies R = \frac{2,000 \times 100}{7,000 \times 2} = 14.285$

or, R = 14.285%

Hence, the required rate of interest = 14.285%

8 0

3 years ago

If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how

Goryan [66]

Rates are used to measure a quantity over another.

<em>The 1.8 million cars use </em> $1.85 \times 10^{10}$ <em> liters each year</em>

Given

$Cars = 1.8\ million$

$d = 17500km$ --- distance

$r = 40miles/gallon$

First, we calculate the number (n) of gallons used by each car

$r = \frac{d}{n}$

Solve for n

$n = \frac{d}{r}$

So, we have:

$n = \frac{17500km}{40miles/gallon}$

$n = \frac{17500km}{40miles}gallon$

Convert miles to kilometers

$n = \frac{17500km}{40km \times 1.60934}gallon$

$n = \frac{17500km}{64.3738km}gallon$

$n = 271.85\ gallon$

The number of gallons (N), used by all the cars is:

$N = n \times cars$

$N = 271.85 \times 1.8\ million$

$N = 489330000$

Convert to liters

$N = 489330000 \times 3.78541L$

$N = 1852314675.3L$

In scientific notation to 2 decimal places, we have:

$N = 1.85 \times 10^{10}L$

<em>Hence, the number of liters used is </em> $1.85 \times 10^{10}$ <em />

Read more about distance and rates at:

brainly.com/question/24659604

4 0

3 years ago

What is the sum of all the whole numbers from 1 to 1000?

Katen [24]

Answer:

So there are 500 pairs of numbers that have a sum of 1001. Thus, the sum of numbers from 1 to 1000 is 500*1001 = 500,500.

Step-by-step explanation:

5 0

3 years ago

8x-5y= 14<br> – 5х+бу = -3

podryga [215]

Answer:

y= 34/23

x= 123/46

Step-by-step explanation:

Solve for x

8x-5y= 14

x= 14/8 +5/8y

Sub x into second equation

– 5х+бу = -3

-5(14/8 +5/8y) + 6y= -3

-29/4 +23/8y = -3

y= 34/23

Sub y into any equation and solve for x

8x=483/23

x= 123/46

4 0

3 years ago

26/55 divided by 34/11

yuradex [85]

The answer is 13/85. You could find out the answer by doing the reprical multiplication.

7 0

2 years ago